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Ierofanga [76]
3 years ago
7

What are all the integers for z/x33 xy/98 and 45

Mathematics
1 answer:
Ymorist [56]3 years ago
7 0

Answer:

im pretty sure i got it correct inverse operations since we can say. 2 2 x x. + - = . If we start with x, then add 2 and subtract 2, ... multiplication and division, squares and square roots (for positive numbers), ... The bottom line is obviously false, and so are all of the previous lines. ... 98 x. -. -. = -. 19. 3 5 3 1 x+ - = 20. 2 3 4 7 x - + = 21. (. )3. 1. 1. 8 x-. = 22

Step-by-step explanation:

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1,323 miles 443 miles and 409 Round to nearest ten
kodGreya [7K]

Answer:

470

Step-by-step explanation:

1323 rounds to 1320  

443 rounds to 440  

409 rounds to 410  

1320 - (440 + 410) =  

1320 - 850 =  

470 <===

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What would the temperature be on an autumn day?
Ket [755]
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Please help me out with this question
julsineya [31]
1) The process of cellular respiration takes place in the mitrochondria.
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4)While there are definitely many more than 4 important molecules, I'm assuming the ones you are looking for are carbohydrates, proteins, Nucleic acids, and lipids.
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Hope this helps! :)
7 0
3 years ago
WORTH 50! WILL AWARD BRAINLIEST! PLEASE SHOW STEPS! THANK YOU!
yanalaym [24]

Answer:

x = 45

Step-by-step explanation:

Re-order terms so constants are on the left
15 * x/9 - 42 =28

Combine multiplied terms into a single fraction
15x/9 - 42 = 28

Cancel terms that are in both the numerator and denominator
5x/3 - 42 = 28


4 0
2 years ago
Consider the differential equationy′′+3y′−10y=0.(a) Find the general solution to this differential equation.(b) Now solve the in
RSB [31]

Answer:

Y= 2e^(5t)

Step-by-step explanation:

Taking Laplace of the given differential equation:

s^2+3s-10=0

s^2+5s-2s-10=0

s(s+5)-2(s+5) =0

(s-2) (s+5) =0

s=2, s=-5

Hence, the general solution will be:

Y=Ae^(-2t)+ Be^(5t)………………………………(D)

Put t = 0 in equation (D)

Y (0) =A+B

2 =A+B……………………………………… (i)

Now take derivative of (D) with respect to "t", we get:

Y=-2Ae^(-2t)+5Be^(5t)   ....................... (E)

Put t = 0 in equation (E) we get:

Y’ (0) = -2A+5B

10  = -2A+5B ……………………………………(ii)

2(i) + (ii) =>

2A+2B=4 .....................(iii)

-2A+5B=10 .................(iv)

Solving (iii) and (iv)

7B=14

B=2

Now put B=2 in (i)

A=2-2

A=0

By putting the values of A and B in equation (D)

Y= 2e^(5t)

6 0
3 years ago
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