In this case, you have to find a common multiple of 3a^2 and 4ab. As only one of the numbers is divisible by two, this means that two cannot go outside of the bracket. The only other aspect that is in both sides of the equation is a, therefore, this goes outside the bracket. The best way to approach this is to divide both sides by a, and this will give you what is inside the bracket. 3a^2 divided by a is 3a, therefore, this is the first aspect in the bracket. -4ab divided by a, leaves -4b. Therefore, these go in the bracket.
3a^2- 4ab simplified is a(3a-4b)
Hope this helps
Answer: x = 35/13
Step-by-step explanation:
Answer:
16/21
Step-by-step explanation:
We are given the equation 3x(5 + 2) = 16.
By order of operations, let's add the two numbers in the parentheses first:
3x(5 + 2) = 16
3x(7) = 16
Now, we must multiply 3x by 7:
3x * 7 = 16
21x = 16
Divide both sides by 21:
x = 16/21
The answer is thus 16/21.
<em>~ an aesthetics lover</em>
X × x = x^2
x × -3 = -3x
3 × x = 3x
3 × -3 = -9
x^2 + 3x - 3x - 9
So I would agree with C because the -3x and the 3x cancel each other out. I hope this helps!