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3 years ago

What are the domain and range of this relation from smallest to largest

Mathematics

1 answer:

torisob [31]3 years ago

4 0

Answer:

x=1,4,3,2
Y=5,2,1,4
Domain 1,4,3,2
Range 5,2,1,4

Step-by-step explanation:

The domain are all the values which can be input into a function. Example y = 2x. To find y, you input some value of x.

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victus00 [196]

How many times your suppose to multiply it by.

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3 years ago

Solve the equation 5y-6=10

BaLLatris [955]

Answer:

y = 3.2

Step-by-step explanation:

Simplifying

5y + -6 = 10

Reorder the terms:

-6 + 5y = 10

Solving

-6 + 5y = 10

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '6' to each side of the equation.

-6 + 6 + 5y = 10 + 6

Combine like terms: -6 + 6 = 0

0 + 5y = 10 + 6

5y = 10 + 6

Combine like terms: 10 + 6 = 16

5y = 16

Divide each side by '5'.

y = 3.2

Simplifying

y = 3.2

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2 years ago

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45 – 15 – 15 = A. 15. B. 0. C. 1. D. 30

Hatshy [7]

45 - 15 - 15 = 45 - 30

45 - 30 = (15)

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3 years ago

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What’s the answer to this

jeyben [28]

It is somewhere in between 7,4 and 4,8

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3 years ago

3. Using techniques from Calculus, show directly that the maximum value of a 1-D Gaussian distribution occurs at the point x = μ

Vilka [71]

Answer:

For a scaler variable, the Gaussian distribution has a probability density function of

p(x |µ, σ² ) = N(x; µ, σ² ) = 1 / 2π× $e^{\frac{-(x-u)^{2}}{2s^{2} } }$

The term will have a maximum value at the top of the slope of the 1-D Gaussian distribution curve that is when exp(0) =1 or when x = µ

Step-by-step explanation:

Gaussian distributions have similar shape, with the mean controlling the location and the variance controls the dispersion

From the graph of the probability distribution function it is seen that the the peak is the point at which the slope = 0, where µ = 0 and σ² = 1 then solution for the peak = exponential function = 0 or x = µ

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3 years ago