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Marat540 [252]
4 years ago
14

6. Name a fraction larger than 1/2 and smaller than 5/8

Mathematics
2 answers:
kap26 [50]4 years ago
6 0

Answer:

3/5 works

Step-by-step explanation:

its in between 1/2 and 5/8

Arte-miy333 [17]4 years ago
4 0

Answer:

it's 9/16 it is in between 1/2 and 3/4

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A line goes through the points (8,9) and (-2,4) .
ipn [44]
A) slope: 1/2
b) y-4=1/2(x+2)
c) y=1/2x+1

5 0
3 years ago
The area of a triangle is 92 and its height is 23 what is its base?
Lera25 [3.4K]

Answer:

7.36

Step-by-step explanation:

Area=92

Height=23

Base=?

Area=1/2*base*height

92=1/2*23*height

92=12.5*height

920/125=height

7.36=height

Pleae mention unit in answer

Mark me as brainliest

5 0
3 years ago
Carrie had $60. as an allowance for the week. She spent 2/5 of it on snacks, and 1/4 on stickets and saved the remainder. How mu
anastassius [24]

Answer:

$ 21

Step-by-step explanation:

Money spent = (2/5) * 60 + (1/4) * 60

                      = 2*12 + 1*15

                      = 24 + 15

                      = $ 39

Money save = 60 - 39 = $ 21

3 0
3 years ago
Advertisements for the Sylph Physical Fitness Center claim that completion of their course will result in a loss of weight (meas
MrMuchimi

Answer:

90% confidence interval for the mean weight loss for the population represented by this sample assuming that the differences are coming from a normally distributed population is [1.989 ,13.5105]

Step-by-step explanation:

The data given is

                        Mean                 Std Dev

Before            177.25                29.325

After              169.50                    22.431

Difference        7.75                    8.598

Hence d`=   7.75 and sd=   8.598

The 90% confidence interval for the difference in means for the paired observation is given by

d` ± t∝/2(n-1) *sd/√n

Here  t∝/2(n-1)=1.895  where n-1= 8-1= 7 d.f

and  ∝/2= 0.1/2=0.05

Putting the values

d` ± t∝/2(n-1) *sd/√n

7.75  ±1.895 *  8.598 /√8

 7.75  ± 5.7605

1.989 ,13.5105

90% confidence interval for the mean weight loss for the population represented by this sample assuming that the differences are coming from a normally distributed population is [1.989 ,13.5105]

3 0
3 years ago
Help I need this answer before the day is over
iren2701 [21]
X=73 y=34

i think that is the answer
4 0
3 years ago
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