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kodGreya [7K]
3 years ago
5

identify the oblique asymptote of f(x) = quantity x squared minus 4 x plus 8 over quantity x plus 2. y = 0 y = x - 2 y = x - 6 n

o oblique asymptote
Mathematics
2 answers:
MissTica3 years ago
8 0

Answer:

Oblique asymptote is y= x- 6

Step-by-step explanation:

f(x)= \frac{x^2-4x+8}{x+2}

To find out ablique asymptote we use long division

                               x  - 6

                              ------------------------------

          x+2                x^2-   4x+   8

                                x^2+  2x

                             ------------------------------ (Subtract it )

                                      -  6x  + 8

                                      -  6x  - 12

                          ------------------------------(Subtract it)

                                              -20

Quotient is the oblique asymptote

Oblique asymptote is y= x- 6

navik [9.2K]3 years ago
5 0
Using long division, f(x) = x - 6 remainder 20
Therefore, oblique asymptote is y = x - 6
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Yes it is .

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then x _> 1.4

which mean x can be any number that is greater than or equal to 1.4 so 2 is correct .

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If f and g are differentiable functions for all real values of x such that f(1) = 4, g(1) = 3, f '(3) = −5, f '(1) = −4, g '(1)
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4 years ago
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ELEN [110]

Answer:

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2 years ago
Solve the right angle trig. round to the nearest tenth.
Tresset [83]

Answer:

x ≈ 58.9

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Geometry</u>

  • [Right Triangles Only] tan∅ = opposite over adjacent

Step-by-step explanation:

<u>Step 1: Define</u>

We are given a right triangle. We can use trig to find the missing side length.

<u>Step 2: Identify Variables</u>

<em>POV from the angle measure</em>

Angle = 23°

Opposite Leg = 25

Adjacent Leg = <em>x</em>

<em />

<u>Step 3: Solve for </u><em><u>x</u></em>

  1. Substitution [tangent]:                    tan23° = 25/x
  2. Multiply <em>x</em> on both sides:                xtan23° = 25
  3. Isolate <em>x</em>:                                          x = 25/tan23°
  4. Evaluate:                                          x = 58.8963
  5. Round:                                             x ≈ 58.9
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3 years ago
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