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3 years ago

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for each babysitting job anna charges 2.50 for bus fare plus $8 per hours she worked. She charged 3.50 for her last babysitting

job. how many hours did she babysit for her last babysitting job. write an equation and solve.

1 answer:

julsineya [31]3 years ago

5 0

8x+2.50=3.50
-2.50 -2.50 subtract both sides by -2.50
8x=1
8. 8 divide both sides by 8
x=1/8

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a rectangle has a width of 4 cm and a length of 8cm is scaled by a factor of 6.what are the side lengths of the scaled copy

vichka [17]

Answer:

$\huge\boxed{\text{Width: } 24 \ \ \ \text{Length: } 32}$

Step-by-step explanation:

When we scale an object by a scale factor, the side lengths become the scale factor times bigger than the previous sides. Therefore, with a scale factor of 6, the side lengths would be multiplied by 6.

$4 \cdot 6 = 24\\\\4 \cdot 8 = 32$

Hope this helped!

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3 years ago

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8+2(5 - x) = <br> Need help

nikdorinn [45]

We can distribute
2(5)+2(-x)=10-2x

we get
8+10-2x=?
18-2x=?

whatever that ? is, we don't know
multiply both sides by -1
2x-18=-?
add 18 to both sides
2x=18-?
divide bth sides by 2
x=9-(?/2)
whatever the left side it, just divide it by 2 and subtract it from 9

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3 years ago

For what value of h is 24=h/10-6

faltersainse [42]

Answer:

h=3

Step-by-step explanation:

h/10 -6 =24

+6 to each side

h/10=30

divide each side by 10

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3 years ago

Alex buys 5.5 yards of blue fabric and 4.5 yards of red fabric. If the blue and red fabric cost the same amount per yard, and al

Law Incorporation [45]

$7.40, if you add 5.5 and 4.5 it will equal 10. Then you divide 74 by 10.

6 0

3 years ago

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Which is equivalent to RootIndex 5 StartRoot 1,215 EndRoot Superscript x?

SOVA2 [1]

Answer:

1,215 Superscript one-fifth x

Step-by-step explanation:

Given:

The expression to simplify is given as:

$(\sqrt[5]{1215})^x$

We know that,

$\sqrt[n]{a} = a^{\frac{1}{n}}$

Here, $n=5, a=1215$

So, $\sqrt[5]{1215} = 1215^{\frac{1}{5}}$

So, the above expression becomes:

$(\sqrt[5]{1215})^x = (1215^{\frac{1}{5}})^x$

Now, using the law of indices $(a^m)^n=a^{(m\times n)}$

Here, $a=1215,m=\frac{1}{5},n=x$

So, the expression is finally simplified to;

$=(1215)^{({\frac{1}{5}}\times x)}\\\\=(1215)^{\frac{1}{5}x}$

Therefore, the second option is the correct one.

$(\sqrt[5]{1215})^x$ = 1,215 Superscript one-fifth x

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3 years ago

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