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koban [17]
3 years ago
12

Solve 4^x-5 = 6 for x using the change of base formula log base b of y equals log y over log b

Mathematics
1 answer:
Ronch [10]3 years ago
6 0

Answer:

4^x-5=6 gives the solution x=\frac{\log(11)}{\log(4)}.

4^{x-5}=6 gives the solution x=\frac{\log(6)}{\log(4)}+5.

Step-by-step explanation:

I will solve both interpretations.

If we assume the equation is 4^{x}-5=6, then the following is the process:

4^x-5=6

Add 5 on both sides:

4^x=6+5

Simplify:

4^x=11

Now write an equivalent logarithm form:

\log_4(11)=x

x=\log_4(11)

Now using the change of base:

x=\frac{\log(11)}{\log(4)}.

If we assume the equation is 4^{x-5}=6, then we use the following process:

4^{x-5}=6

Write an equivalent logarithm form:

\log_4(6)=x-5

x-5=\log_4(6)

Add 5 on both sides:

x=\log_4(6)+5

Use change of base formula:

x=\frac{\log(6)}{\log(4)}+5

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The correct question is:

Suppose x = c1e^(-t) + c2e^(3t) a solution to x''- 2x - 3x = 0 by substituting it into the differential equation. (Enter the terms in the order given. Enter c1 as c1 and c2 as c2.)

Answer:

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is a solution to the differential equation

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Step-by-step explanation:

We need to verify that

x = c1e^(-t) + c2e^(3t)

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We differentiate

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Let us do that.

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