For margin of error to be a maximum of 3:
3 = z*(SD / sqrt(n)), where z is the z-score, SD is the standard deviation and n is the sample size.
z = 1.96 for a 95% confidence interval, and we are given SD = 15.
3 = 1.96*15/sqrt(n)
sqrt(n) = 9.8
n = 96.04 ~ 96 commercials.
Answer:
24316
Step-by-step explanation:
24316 is your answer. I really hope this helps. Stay hydrated fam.
Answer:
105/330 = 21/66 = 7/22
7/22 is the answer I think
Step-by-step explanation:
n(U) = 330
n(A) = 85
n(B) = 200
n(A n B) = 60
Now,
n(A U B) = n(A) + n(B) - n(A n B)
or, n(A U B) = 85 + 200 - 60
or, n(A U B) = 285 - 60 = 225
Now,
n(A U B) compliment = n(U) - n(A U B)
n(A U B) compliment = 330 - 225
so, n(A U B) compliment = 105
Now,
probability = 105/330
Answer:
2x^2 + 4x+2
Step-by-step explanation:
f(x) = 2x^2 + x and g(x) = 3x + 2
f(x) + g(x) = 2x^2 + x + 3x + 2
Combine like terms
= 2x^2 + 4x+2
Answer:
1806 seats.
Step-by-step explanation:
From the question given above, the following data were obtained:
Row 1 = 24 seats
Row 2 = 27 seats
Row 3 = 30 seats
Total roll = 28
Total number of seat =?
From the above data, we can liken the roll to be in arithmetic progress.
Also, we are asked to determine the total number of seats in the theater.
Thus the sum of the sequence can be written as:
Roll 1 + Roll 2 + Roll 3 +... + Roll 28 i.e
24 + 27 + 30 +...
Thus, we can obtain obtained the total number of seats in the theater by applying the sum of arithmetic progress formula. This can be obtained as follow:
First term (a) = 24
Common difference (d) = 2nd term – 1st term
Common difference (d) = 27 – 24 = 3
Number of term (n) = 28
Sum of the 28th term (S₂₈) =?
Sₙ = n/2 [2a + (n –1)d]
S₂₈ = 28/2 [2×24 + (28 –1)3]
S₂₈ = 14 [48 + 27×3]
S₂₈ = 14 [48 + 81]
S₂₈ = 14 [129]
S₂₈ = 1806
Thus, the number of seats in the theater is 1806.