Answer:The answer is choice 3
Step-by-step explanation:
The same thing to the other side
54, 36, 24 are the 1st 3 element of a geometric progression with 2/3 as a common ratio: PROOF:
the 1st term is 54, (a₁= 54) the 2nd term a₂ = 24, then
(a₂ = a₁.r) or 36 = 54.r → r= 36/54 = 2/3. Same logique for the 3rd term.
So 2/3 is common ratio. We know that :U(n) = a.(r)ⁿ⁻¹. Then if a =54 and r = x (given by the problem), then f(x) = 54.xⁿ⁻¹
n, being the rank of any element of this geometric progression
Answer:
![\Large\text{The hypotenuse is}\ \sqrt{41}\ ft\approx6.4\ ft](https://tex.z-dn.net/?f=%5CLarge%5Ctext%7BThe%20hypotenuse%20is%7D%5C%20%5Csqrt%7B41%7D%5C%20ft%5Capprox6.4%5C%20ft)
Step-by-step explanation:
![\text{Use the Pythagorean theorem:}](https://tex.z-dn.net/?f=%5Ctext%7BUse%20the%20Pythagorean%20theorem%3A%7D)
![a^2+b^2=c^2](https://tex.z-dn.net/?f=a%5E2%2Bb%5E2%3Dc%5E2)
![\text{a, b - legs}\\\text{c - hypotenuse}](https://tex.z-dn.net/?f=%5Ctext%7Ba%2C%20b%20-%20legs%7D%5C%5C%5Ctext%7Bc%20-%20hypotenuse%7D)
![\text{We have the legs 4ft and 5ft. Substitute:}](https://tex.z-dn.net/?f=%5Ctext%7BWe%20have%20the%20legs%204ft%20and%205ft.%20Substitute%3A%7D)
![c^2=4^2+5^2\\\\c^2=16+25\\\\c^2=41\to c=\sqrt{41}](https://tex.z-dn.net/?f=c%5E2%3D4%5E2%2B5%5E2%5C%5C%5C%5Cc%5E2%3D16%2B25%5C%5C%5C%5Cc%5E2%3D41%5Cto%20c%3D%5Csqrt%7B41%7D)