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2 years ago

Help!!!!!!!!!!!!!!!!!!!!!!!!! and I'm giving brainly thxxxxx

Mathematics

1 answer:

mash [69]2 years ago

6 0

Answer:

the 3 is in the hundred thousands

Step-by-step explanation:

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Determine whether segments with lengths of 27, 28, and 7 form a triangle. If so, classify the triangle as acute, right, or obtus

gizmo_the_mogwai [7]

Answer:

Step-by-step explanation:

triangle

4 0

3 years ago

What are two expressions that are equivalent to 6(5j + 2 + j)?<br><br><br><br>

ziro4ka [17]

Answer:

1. 30j+12+6j

2. 36j+12

3. 6(6j+2)

Step-by-step explanation:

1. You just multiply so... 6x5j ... 6x2 ... 6xj

2. you multiply and then simplify so first you have 30j+12+6j, so you add like terms so... 30j+6j= 36j and then +12

3. you do what's in the parentheses first so 5j+j=6j so .... 6(6j+2)

5 0

3 years ago

To estimate the mean height μ of male students on your campus,you will measure an SRS of students. You know from government data

nexus9112 [7]

Answer:

a) $\sigma = 0.167$

b) We need a sample of at least 282 young men.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by

$Z = \frac{X - \mu}{\sigma}$

This Zscore is how many standard deviations the value of the measure X is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

(a) What standard deviation must x have so that 99.7% of allsamples give an x within one-half inch of μ?

To solve this problem, we use the 68-95-99.7 rule. This rule states that:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviations of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we want 99.7% of all samples give X within one-half inch of $\mu$ . So $X - \mu = 0.5$ must have $Z = 3$ and $X - \mu = -0.5$ must have $Z = -3$ .

$Z = \frac{X - \mu}{\sigma}$

$3 = \frac{0.5}{\sigma}$

$3\sigma = 0.5$

$\sigma = \frac{0.5}{3}$

$\sigma = 0.167$

(b) How large an SRS do you need to reduce the standard deviationof x to the value you found in part (a)?

You know from government data that heights of young men are approximately Normal with standard deviation about 2.8 inches. This means that $\sigma = 2.8$