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Pachacha [2.7K]
3 years ago
8

:Which graph shows the solutions the following inequality?: 4d - 6 < 18

Mathematics
2 answers:
RSB [31]3 years ago
8 0

4d - 6 < 18 \\ d < 6

Step2247 [10]3 years ago
6 0

Answer:

You made me get it wrong

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To determine whether a graph of a relation is also a function, Shayla declares that the y-axis is a vertical line and counts the
Mars2501 [29]

Answer:

No.

Step-by-step explanation:

The function is any equivalence relation in which there is only one output for every input. This means that the domain must be exhausted in order to gain all the elements of the range and each element of domain gets mapped to only one of the elements of the range. Vertical line test is used to determine whether a graph is a function or not. This test requires that vertical lines parallel to y-axis and including y-axis be drawn on the graph to see that each vertical line intersects the graph only once. This must be true for all the elements of the domain. Therefore, vertical line test requires to draw numerous vertical lines other than the y-axis since the definition of the function requires that. In short, mathematically, there will be a need for infinite number of vertical lines to perform the test. Therefore, Shayla is not applying the vertical line test correctly!!!

8 0
3 years ago
Since ABCD is a parallelogram, the two pairs of _________ sides (AB¯ and CD¯, as well as AD¯ and BC¯) are congruent. Then, since
Marysya12 [62]

Answer:

1. Opposite

2. angle-side-angle criterion

Step-by-step explanation:

Since ABCD is a parallelogram, the two pairs of <u>(opposite)</u> sides (AB¯ and CD¯, as well as AD¯ and BC¯) are congruent. Then, since ∠9 and ∠11 are vertical angles, it can be concluded that ∠9≅∠11. Since ABCD is a parallelogram, AB¯∥CD¯. Since ∠2 and ∠5 are alternate interior angles along these parallel lines, the Alternate Interior Angles Theorem allows that ∠2≅∠5. Since two angles of △AEB are congruent to two angles of △CED, the Third Angles Theorem supports that ∠8≅∠3. Therefore, using the <u>(angle-side-angle criterion)</u>, it can be stated that △AEB≅△CED. Then, applying the definition of congruent triangles, it can be stated that AE¯≅CE¯, which makes E the midpoint of AC¯. Use a similar argument to prove that △AED≅△CEB; then it can be concluded that E is also the midpoint of BD¯. Since the midpoint of both line segments is the same point, the segments bisect each other by definition. Match each number (1 and 2) with the word or phrase that correctly fills in the corresponding blank in the proof.

A parallelogram posses the following features:

   1. The opposite sides are parallel.

   2. The opposite sides are congruent.

   3. It has supplementary consecutive angles.

   4. The diagonals bisect each other.

7 0
3 years ago
A circle has its center at the center of a square with 12-inch sides. Using 3.14 for pi, find the area of the square not covered
Dmitrij [34]
So first, find the area of the square. 12x12= 144inches^2
Then find the area of the circle. To do this we use pi x r^2. The radius of the circle is 6 inches. Pi x 6^2 = 113.04inches^2.
144 - 113.04 = 30.6, so your answer is 30.6 inches^2

The circles circumference is worked out by using pi x d. The diameter is 12 inches, so 3.14x12 = 37.68 inches.
The squares perimeter is 12 x 4 = 48 inches.
If you round up the circumference of the circle to the nearest integer, you get 38 inches. The ratio would therefore be, 38:48, which can be rounded down to 19:24 :)
5 0
3 years ago
Solve for x!! help this is due soon
Umnica [9.8K]

Answer

91

Step-by-step explanation:

62+27+x=180

6 0
3 years ago
segment MN is shown. Point M is located at (7,6). Point N is located at (7,-4) What is the midpoint segment of MN
Luda [366]

Answer:

The midpoint of MN is <u>(7,1)</u>

Add the x coordinates 7+7=14 then you divide that by 2 giving you 7.

Then you add the y coordinates together 6+(-4)=2 then divide by 2 and that gives you 1. Therefore the answer is (7,1)

6 0
2 years ago
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