Question

if trangle pqr is translated 4 units to the right to form triangle p'q'r' how are the values on the orderd pairs affected by the translation​

Answer 1

Answer:

The x-coordinate of each point will increase by 4.

Step-by-step explanation:

So Triangle PQR is being translated 4 units to the right. Since we are going to the right, this is a shift on the x-coordinate.

And since we're going 4 units, every x-coordinate is going to be added by 4.

In other words, if we have:

$A(x,y)$

Then the new coordinate, A', is:

$A(x,y)\rightarrow A' (x+4,y)$

So, let's find the new coordinates of each point.

Point P is (-5,6). So:

$P(-5,6)\rightarrow P'(-5+4,6)=P'(-1,6)$

The new Point P is at (-1,6).

Point Q is at (2,6). So:

$Q(2,6)\rightarrow Q'(2+4,6)=Q'(6,6)$

The new Point Q would be at (6,6).

And Point R is at (-3,2). So:

$R(-3,2)\rightarrow R(-3+4,2)=R(1,2)$

The new Point R is at (1,2).

And we're done!

Answer 2

Since we are translating 4 units to the right, all x-values are going to be added by 4.

Point P: (-5, 6) -> (-5 + 4, 6) -> (-1, 6)

Point Q: (2, 6) -> (2 + 4, 6) -> (6, 6)

Point R: (-3, 2) -> (-3 + 4, 6) -> (1, 2)

Best of Luck!