1) X^5Y/X^5= X^0Y= Y (Anything raise to power of 0 is 1)
2)(3mn)^1= 3mn
3)m^-4xM^5= M^-4+5= M
4) 5^-4x5^4= 5^-4+4= 5^0= 1
5) nm^3/n^3m= n^1-3m^3-1= n^-2m^2= m^2/n^2
6) (-2)^0= 1
therefore number 4 and 6 has the value of 1
You can use the formula for conditional probability as Puzzling did. However in this problem it is easier just to restrict yourself and enumerate the cases that are left.
<span>There are 4 jacks. One of them is a heart. So the probability is 1/4. </span>
<span>If you want to look at what the formula for conditional probability does, it adjusts your probability by restricting the "universe". </span>
<span>P(heart and jack)/P(jack) </span>
<span>= (1/52)/(4/52) = 1/4</span>
F(x) + k - Moves the graph k units up.
k f(x) stretches the graph parallel to y-axis by a facor k
f (kx) stretches the graph by a factor 1/k parallel to x-axis
f(x + k) moves the graph 3 units to the left.
For k negative the first one moves it k units down
for second transform negative does same transfoormation but also reflects the graph in the x axis
For the third transform negative k :- same as above but also reflects in y axis
4th transform - negative k moves graph k units to the right
The amount of money he lose on the last tool set is: $30.60.
<h3>Amount lose</h3>
Using this formula
Amount lose=Original amount paid -Selling price
Where:
Original amount paid=$54.60
Selling price=$24.00
Let plug in the formula
Amount lose=$54.60-$24.00
Amount lose=$30.60
Therefore the amount of money he lose on the last tool set is: $30.60.
Learn more about amount lose here:brainly.com/question/11872053
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My answer is a and c becuase they equal the same on each side
