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Kazeer [188]
3 years ago
10

Find the area of the triangle that has a base of 16 yd and a height of 9 yd.

Mathematics
1 answer:
elena55 [62]3 years ago
7 0
Letter A Hope this helps
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Find the surface area of the prism. Length: 5 width: 8 height: 12 in
frez [133]

Answer:

The only answer I have for this could be 392in²

7 0
3 years ago
I'LL GIVE BRAINLIEST !!! FASTERR !<br><br>​
Talja [164]

Answer:

opt. B

Step-by-step explanation:

g=60 because equilateral triangle ang=60

<KMN=120 because of linear pair

<h= 180-(120+29)= 31

g+h= 60+31= 91

3 0
3 years ago
Factor completely. y2 - xy - 56x2
aliina [53]
For this case we have the following expression:
 y2 - xy - 56x2
 Rewriting we have the factored expression, which is given by:
 (7x + y) (y-8x)
 Checking we have:
 7xy - 56x ^ 2 + y ^ 2 - 8xy
 y ^ 2 - xy - 56x ^ 2 (OK)
 Answer:
 
The factored expression is given by:
 
y2 - xy - 56x2 = (7x + y) (y-8x)
5 0
3 years ago
Y multiple 3 = 3/5 so y =
Rasek [7]
Y × 3 = 3 / 5
y = 3 / 5×3
y = 3/15
y = 1/5

In short, Your Answer would be 1/5

Hope this helps!
7 0
3 years ago
Read 2 more answers
A survey of 85 families showed that 36 owned at least one DVD player. Find the 99% confidence interval estimate of the true prop
attashe74 [19]

Answer:

0.424 - 2.58\sqrt{\frac{0.424(1-0.424)}{85}}=0.286

0.424 + 2.58\sqrt{\frac{0.424(1-0.424)}{85}}=0.562

The 99% confidence interval would be given by (0.286;0.562)

Step-by-step explanation:

Information given:

X= 36 represent the families owned at least one DVD player

n= 85 represent the total number of families

\hat p=\frac{36}{85}= 0.424 represent the estimated proportion of families owned at least one DVD player

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by \alpha=1-0.99=0.01 and \alpha/2 =0.05. And the critical value would be given by:

z_{\alpha/2}=-2.58, z_{1-\alpha/2}=2.58

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

If we replace the values obtained we got:

0.424 - 2.58\sqrt{\frac{0.424(1-0.424)}{85}}=0.286

0.424 + 2.58\sqrt{\frac{0.424(1-0.424)}{85}}=0.562

The 99% confidence interval would be given by (0.286;0.562)

8 0
3 years ago
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