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DanielleElmas [232]
4 years ago
5

Find the product 2y^2(3x+5z)

Mathematics
2 answers:
fgiga [73]4 years ago
8 0
2y^2 (3x+5z)
6xy^2 + 10zy^2
artcher [175]4 years ago
7 0

Answer:

Product of  expression 2y² (3x+5z) is 6y²x + 10y²z .

Step-by-step explanation:

As given the expression in the question be as follow .

= 2y² (3x+5z)

First open the bracket and simplify the above expression

= 2y² × 3x + 2y² × 5z

= 6y²x + 10y²z

Therefore the product of the expression 2y²(3x+5z) is 6y²x + 10y²z .

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I need help with number 33 thank u!
Rufina [12.5K]

Answer:

C. 2,150

Step-by-step explanation:

We know that out of 120 passengers, 86 were satisfied with the service.

To find the percentage amount of passengers who were satisfied, we can divide 86 by 120 and get 0.716 repeating (about 71.6%).

Then, we can multiply the total number of passengers, 3,000, by that number and get 2,150.

7 0
4 years ago
Convert 27day 8hour into second
Nataliya [291]
27 days and 8 hours = 656 hours
27 x 24 = 648
648 + 8 = 656
24 hours = 3,600 seconds
656 x 3,600 = 2,361,600 seconds

The answer is 2,361,600 seconds.
7 0
3 years ago
In 2001 , chipper had 102 runs batted in. In 2008, Chipper had only 75 runs batted in. Calculate the percent change in runs batt
DerKrebs [107]

Answer:

The percent change in runs batted in from 2001 to 2008 is 26.47%

Step-by-step explanation:

The number of runs chipper batted in the year 2001  = 102 runs

The number of runs chipper batted in the year 2008  = 75 runs

Here, so the Change in the runs batted

= Runs Batted in year 2001 - Runs batted in the year 2008

= 102 runs - 75 runs  =  27 runs

Now, The percentage change in the run = = \frac{\textrm{Change in the batted run from 2001 to 2008}}{\textrm{Total number of batted runs in 2001}}  \times 100

= \frac{27}{102}  \times 100 = 26.47

or, The percentage change = 26.47%

Hence, the percent change in runs batted in from 2001 to 2008 is 26.47%

5 0
3 years ago
PLEASE FAST HELP PLS I BEG U
cricket20 [7]

Answer:A.,C.,D that is the answer

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Write the product in standard form. ( 9 + 5i)( 9 + 8i)
disa [49]
<span>( 9 + 5i)( 9 + 8i)
= 9(9+8i)+5i(9+8i)
= 81+72i+45i+40i^2
= 81+117i+40(-1)
= 81-40+117i
= 41+117i. Answer</span>
8 0
4 years ago
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