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3 years ago

Given

Mathematics

1 answer:

vesna_86 [32]3 years ago

3 0

The answer is B. Use the u.s rule to solve the balance after payments for the 100th and 180th

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The quotient of the opposite of 30 and 6, plus the opposite of 8

vodomira [7]

First change 30 and 6 to -30 and -6. Now divide them to get positive 5. The opposite of 8 is -8. Now you add 5 to -8. This gives you -3.

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3 years ago

81a raised to the power of 2 minus 25

muminat

81a²-25 would be the answer I'm pretty sure. Hopefully I helped.

8 0

3 years ago

Read 2 more answers

Determine the projection of u=1.6i+3.3j in the v=-2.1i-0.5j direction

Lina20 [59]

The projection of $\vec u$ onto $\vec v$ is

$\mathrm{proj}_{\vec v}(\vec u)=\dfrac{\vec u\cdot\vec v}{\vec v\cdot\vec v}\vec v$

We have

$\vec u\cdot\vec v=1.6\cdot(-2.1)+3.3\cdot(-0.5)=-5.01$

$\vec v\cdot\vec v=\|\vec v\|^2=(-2.1)^2+(-0.5)^2=4.66$

$\implies\mathrm{proj}_{\vec v}(\vec u)=\dfrac{-5.01}{4.66}\vec v\approx2.26\,\vec\imath+0.54\,\vec\jmath$

8 0

4 years ago

Evaluate the expression for the given value of the variable. y -8 +12;y=32

MrMuchimi

Answer:

Step-by-step explanation:

32-8+12=24+12=36

4 0

3 years ago

Suppose that 10% of the undergraduates at a certain university are foreign students, and that 25% of the graduate students are f

Deffense [45]

Answer:

0.6154 = 61.54% probability that the student is an undergraduate

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Foreign

Event B: Undergraduate.

There are four times as many undergraduates as graduate students

So 4/5 = 80% are undergraduate students and 1/5 = 20% are graduate students.

Probability the student is foreign:

10% of 80%

25% of 20%. So

$P(A) = 0.1*0.8 + 0.25*0.2 = 0.13$

Probability that a student is foreign and undergraduate:

10% of 80%. So

$P(A \cap B) = 0.1*0.8 = 0.08$

What is the probability that the student is an undergraduate?

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.08}{0.13} = 0.6154$

0.6154 = 61.54% probability that the student is an undergraduate

8 0

3 years ago