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kobusy [5.1K]
3 years ago
9

The graphs below have the same shape. What is the equation of the blue

Mathematics
1 answer:
zhenek [66]3 years ago
5 0

Answer:

g(x)=(x-2)^2

Step-by-step explanation:

The complete question in the attached figure

we have that

f(x)=x^2

This is a vertical parabola open upward

The vertex represent a minimum

The vertex is the origin (0,0)

The function g(x) have the same shape of f(x)

The vertex of the function g(x) is the point (2,0)

so

The transformation of f(x) to g(x) is

f(x) ----> g(x)

(0,0) ----> (2,0)

The rule of the transformation is

(x,y) ----> (x+2,y)

That means ----> The transformation is a translation 2 units at right

therefore

The function g(x) is equal to

g(x)=(x-2)^2

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The sum of two numbers is 50. The first number is 43 less than twice the second number. Write and solve a system of equations to
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Answer: 19 and 31

Step-by-step explanation: Make the first number x, the second number y.

The sum of x and y is 50: x+y=50

x is 43 less than 2y: x=2y-43

replace x in equation x+y=50 with x=2y-43: 2y-43+y=50

combine like terms: 3y-43=50

add 43 to both sides: 3y=93

divide both sides by 3: y=31

replace y in equation x+y=50 with y=31: x+31=50

subtract 43 31 from both sides: x=19

the solution to the question is the first number is 19, the second number is 31

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3 years ago
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B.   Scale reads 3.5oz which means 3.5oz more than 28oz. So rejected.

C.   Scale reads -3.3oz which means less  than 28oz, So accepted.

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A box contains four $1 and six $5 bills. if three bills are selected at random without replacement, find the probability that al
myrzilka [38]

Answer:

C.1/6

Step-by-step explanation:

Initially the box has four $1 and six $5 bills. The probability of selecting a $5 bill in the first trial would be given as;

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= (6)/(4+6) = 3/5

If in the first attempt we actually pick a $5 bill, the number of $5 bills will reduce by one to 5. Now, the probability of picking a $5 bill in the second attempt will be given as;

(new number of $5 bills) / (new total number of bills)

= (5)/(4+5) = 5/9

The new number of $5 bills will now be; 6 - 2 = 4 since we have already picked 2 without replacing them.

Now, the probability of picking a $5 bill in the third attempt will be given as;

(new number of $5 bills) / (new total number of bills)

= (4)/(4+4) = 1/2

Since the three attempts are independent, the probability of picking  all three $5 bills is;

3/5 * 5/9 * 1/2 = 1/6

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