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romanna [79]
2 years ago
7

A box contains four $1 and six $5 bills. if three bills are selected at random without replacement, find the probability that al

l three are $5 bills.
A.27/125 B.1/4 C.1/6 D3/5
Mathematics
1 answer:
myrzilka [38]2 years ago
7 0

Answer:

C.1/6

Step-by-step explanation:

Initially the box has four $1 and six $5 bills. The probability of selecting a $5 bill in the first trial would be given as;

(number of $5 bills) / (total number of bills)

= (6)/(4+6) = 3/5

If in the first attempt we actually pick a $5 bill, the number of $5 bills will reduce by one to 5. Now, the probability of picking a $5 bill in the second attempt will be given as;

(new number of $5 bills) / (new total number of bills)

= (5)/(4+5) = 5/9

The new number of $5 bills will now be; 6 - 2 = 4 since we have already picked 2 without replacing them.

Now, the probability of picking a $5 bill in the third attempt will be given as;

(new number of $5 bills) / (new total number of bills)

= (4)/(4+4) = 1/2

Since the three attempts are independent, the probability of picking  all three $5 bills is;

3/5 * 5/9 * 1/2 = 1/6

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So I would have to say the the same except you have to flip the inequality sign like this:

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\geqslant  \\

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And if that doesnt somehow work and the question is wording it wrong then

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So to get from standard form to Slope intercept form (y=mx+b) these are the steps:

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