Question

It's urgent please help! find the perimeter of the triangle with vertices listed (-5,2), (3,2), (1,6)

Answer 1

Answer:

19.68

Explanation:

Given:

Vertices : (-5,2), (3,2), (1,6)

To get the length of each side, we need to

Length = √(x2 - x1)^2 + (y2 - y1)^2

calculate the distance between the points ;

Taking, (-5,2), (3,2)

L1 = √(3 -(-5))^2+ (2 -2)^2

L1 =√(3 + 5)^2 + 0^2

L1 = √8^2 = √64 = 8

Taking L2 ; (3,2), (1,6)

L2 = √(1 -3)^2 + (6 - 2)^2

L2 = √ (-2)^2 + 4^2

L2 = √ 4 + 16

L2 = √20 = 4.47

Taking L3 ; (-5,2), (1,6)

L3 = √(1 - (-5))^2 + (6 - 2)^2

L3 = √(1 + 5)^2 + (6 - 2)^2

L3 = √6^2 + 4^2

L3 = √36 + 16 = √52

L3 = 7.21

Therefore, perimeter = L1 + L2 + L3

8 + 4.47 + 7.21 = 19.68

Answer 2

QUICK ANSWER: answer is 19.68.