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3 years ago

7

In a baseball league consisting of 12 teams, each team plays each of the other teams twice. How many games will be played? There

will be games played. Enter your answer in the answer box and then click Check Answer Clear All All parts showing bmt12 0102.ppt bmt12 data-8 30 201.. xlsx data-8 30 201....xlsx Macbook

1 answer:

saul85 [17]3 years ago

4 0

Answer:

132 games played.

Step-by-step explanation:

Let x be the

We have been given that in a baseball league consisting of 12 teams, each team plays each of the other teams twice.

Since there are 12 teams, so each team will play with $(12-1)$ teams except itself.

The total number of games played would be 12 times $(12-1)$ :

$\text{The total number of games played}=12(12-1)$

$\text{The total number of games played}=12(11)$

$\text{The total number of games played}=132$

Therefore, there will be 132 games played.

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Geometry math question no Guessing and Please show work

MAXImum [283]

If the point P(x, y) partitions the segment AB in the ratio 1 : 1, then the point P is midpoint of segment AB.

The formula of a midpoint of segment:

$A(x_A;\ y_A),\ B(x_B,\ y_B)\\\\P_{AB}\left(\dfrac{x_A+x_B}{2};\ \dfrac{y_A+y_B}{2}\right)$

We have:

$A(13,\ 1)\to x_A=13,\ y_A=1\\B(-5,\ -3)\to x_B=-5,\ y_B-3\\\\P\left(\dfrac{13+(-5)}{2};\ \dfrac{1+(-3)}{2}\right)\to P\left(\dfrac{8}{2};\ \dfrac{-2}{2}\right)\to P(4,\ -1)$

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4 years ago

Arjun sells handmade ceramic mugs he Mark's them up by 60% to make a profit they cost $8 in materials how much do this mugs cost

Reptile [31]

Answer:

$12.80

Step-by-step explanation:

Before markup: $8

After markup: $8 x 160% = $12.80

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3 years ago

In the △ABC, the height AN = 24 in, BN = 18 in, AC = 40 in. Find AB and BC. Consider all possible cases. Case 1 : N∈BC, AB = __,

aivan3 [116]

Answer:

Case 1:

$AB = 30$

$BC = 50$

Case 2:

$AB = 15.9$

$BC = 36.7$

Case 3: Not possible

Step-by-step explanation:

Given

See attachment for illustration of each case

Required

Find AB and BC

Case 1:

Using Pythagoras theorem in ANB, we have:

$AB^2 = AN^2 + BN^2$

This gives:

$AB^2 = 24^2 + 18^2$

$AB^2 = 576 + 324$

$AB^2 = 900$

Take square roots of both sides

$AB = \sqrt{900$

$AB = 30$

To calculate BC, we consider ANC, where:

$AC^2 = AN^2 + NC^2$

$40^2 = 24^2 + NC^2$

$1600 = 576 + NC^2$

Collect like terms

$NC^2 = 1600 - 576$

$NC^2 = 1024$

Take square roots

$NC = \sqrt{1024$

$NC = 32$

So:

$BC = NC + BN$

$BC = 32 + 18$

$BC = 50$

Case 2:

Using Pythagoras theorem in ANB, we have:

$AN^2 = AB^2 + BN^2$

This gives:

$24^2 = AB^2 + 18^2$

$576 = AB^2 + 324$

Collect like terms

$AB^2 = 576 - 324$

$AB^2 = 252$

Take square roots of both sides

$AB = \sqrt{252$

$AB = 15.9$

To calculate BC, we consider ABC, where:

$AC^2 = AB^2 + BC^2$

$40^2 = 252 + BC^2$

$1600 = 252 + BC^2$

Collect like terms

$BC^2 = 1600 - 252$

$BC^2 = 1348$

Take square roots

$BC = \sqrt{1348$

$BC = 36.7$

Case 3:

This is not possible because in ANC

The hypotenuse AN (24) is less than AC (40)

3 0

3 years ago

Solve for x.<br> 6x + 5 = -x + 40<br> B. x= -5<br> A. x = -9<br> D. x= 9<br> C. x = 5

denis23 [38]

C, x=-5, hope this helps

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3 years ago

HOMEWORK HELP NEED IT FAST PLEASE!

Lunna [17]

I hope this helps you

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3 years ago

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