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Gnoma [55]
3 years ago
14

Question 10 of 10

Mathematics
1 answer:
docker41 [41]3 years ago
8 0

Answer:

4

Step-by-step explanation:

\frac{ \sqrt{9} \times  \sqrt{144}  }{ \sqrt{81 } }  \\  \\  \frac{3 \times 12}{9}  \\  \\  \frac{36 }{9}  \\  \\  = 4

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11/6 + -2/5 +-13/10?
Goshia [24]

Answer:

<h2><u><em>2/15 </em></u></h2>

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<h2><u><em>Step-by-step explan</em></u>ation:</h2>

11/6 + -2/5 +-13/10?

11/6 + (-2/5) + (-13/10)

43/30 - 13/10

2/15

6 0
2 years ago
Nnnn hnknbghvbytvbnyufvbyggyftctfcvtdc
zlopas [31]

Answer:

thx

Step-by-step explanation:

7 0
3 years ago
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Whats the step by step answer to this equation i got -25 but its supposed to be positive not negative
andreev551 [17]

Answer:

25

Step-by-step explanation:

  • - 6/5x = -30               ⇒ multiply both sides by -1
  • 6/5x = 30                  ⇒ multiply both sides by 5
  • 6x = 5*30
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6 0
3 years ago
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olga55 [171]
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3 years ago
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What is a cubic polynomial function with zeros 3,3 and -3? show your work.​
Brums [2.3K]

Answer:

Cubic polynomial function with zeros 3,3 and -3 is \mathbf{x^3-3x^2-9x+27=0}

Step-by-step explanation:

We need to find a cubic polynomial function with zeros 3,3 and -3.

If zeros of polynomial are: 3,3,and -3

we can write:

x=3, x=3, x=-3

Or

We can write:

x-3=0, x-3=0, x+3=0

Now, we can write them as:

(x-3)(x-3)(x+3)=0

Multiplying the terms, we can find the polynomial:

(x-3)(x-3)(x+3)=0\\(x(x-3)-3(x-3))(x+3)=0\\(x^2-3x-3x+9)(x+3)=0\\(x^2-6x+9)(x+3)=0\\x(x^2-6x+9)+3(x^2-6x+9)=0\\x^3-6x^2+9x+3x^2-18x+27=0\\x^3-6x^2+3x^2+9x-18x+27=0\\x^3-3x^2-9x+27=0

So, cubic polynomial function with zeros 3,3 and -3 is \mathbf{x^3-3x^2-9x+27=0}

4 0
3 years ago
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