What is the factored form of 6.12 + 118 - 10? (2x +

Mathematics

2 answers:

Firlakuza [10]4 years ago

3 0

114.12 is the answer hope this helps

Alexxandr [17]4 years ago

3 0

1 Simplify 6.12+118 to 124.12.

124.12-10

2 Simplify.

114.12

I hope this is what you want

I hope it helps :)

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3 years ago

How do you factor x2-49 ?

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Question
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x² - 49

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Form into 2 perfect squares
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x² - 7²

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Formula
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a² - b² = (a + b) (a - b)

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Apply the formula
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Answer: (x + 7)(x - 7)
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3 years ago

Read 2 more answers

Compute the flux of curl(F) through the part of the paraboloid z = x 2 + y 2 that lies below the plane z = 4 with upward-pointin

kkurt [141]

Parameterize this surface (call it S) by

$\mathbf s(u,v)=u\cos v\,\mathbf i+u\sin v\,\mathbf j+u^2\,\mathbf k$

with $0\le u\le2$ and $0\le v\le2\pi$ .

The normal vector to S is

$\mathbf n=\dfrac{\partial\mathbf s}{\partial u}\times\dfrac{\partial\mathbf s}{\partial v}=-2u^2\cos v\,\mathbf i-2u^2\sin v\,\mathbf j+u\,\mathbf k$

Compute the curl of F :

$\nabla\times\mathbf F=-2\,\mathbf i+3\,\mathbf j+5\,\mathbf k$

So the flux of curl(F) is

$\displaystyle\iint_S(\nabla\times\mathbf F)\cdot\mathrm d\mathbf S=\int_0^{2\pi}\int_0^2(\nabla\times\mathbf F)\cdot\mathbf n\,\mathrm du\,\mathrm dv$

$=\displaystyle\int_0^{2\pi}\int_0^2(5u+4u^2\cos v-6u^2\sin v)\,\mathrm du\,\mathrm dv=\boxed{20\pi}$

Alternatively, you can apply Stokes' theorem, which reduces the surface integral of the curl of F to the line integral of F along the intersection of the paraboloid with the plane z = 4. Parameterize this curve (call it C) by

$\mathbf r(t)=2\cos t\,\mathbf i+2\sin t\,\mathbf j+3\,\mathbf k$