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3 years ago

Translating between Tables,

Mathematics

1 answer:

wel3 years ago

8 0

Answer:

Table of values

$x \to y$

$0 \to -5$

$1 \to -2$

$2 \to 1$

$3 \to 4$

$4 \to 7$

$5 \to 10$

<em>See attachment for graph</em>

Step-by-step explanation:

Given

$y = 3x - 5$

Solving (a): Make a table

Considering the values of x from 0 to 5, we have:

When $x = 0$

$y = 3x - 5 \to 3 * 0 - 5 = -5$

When $x = 1$

$y = 3x - 5 \to 3 * 1 - 5 = -2$

When $x = 2$

$y = 3x - 5 \to 3 * 2 - 5 = 1$

When $x = 3$

$y = 3x - 5 \to 3 * 9 - 5 = 4$

When $x = 4$

$y = 3x - 5 \to 3 * 4 - 5 = 7$

When $x = 5$

$y = 3x - 5 \to 3 * 5 - 5 = 10$

So, we have:

$x \to y$

$0 \to -5$

$1 \to -2$

$2 \to 1$

$3 \to 4$

$4 \to 7$

$5 \to 10$

Solving (b): The graph

See attachment

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Answer:

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Step-by-step explanation:

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See the attached figure please.
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Answer:

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Step-by-step explanation:

We need to find an equation of the circle that satisfies the stated conditions. (Give your answer in standard notation.)

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The general equation of circle is: $(x-h)^2+(y-k)^2=r^2$

Where r is radius and (h,k) is centre of circle.

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$Midpoint=(\frac{x_1+x_2}{2} ,\frac{y_1+y_2}{2} )\\Midpoint=(\frac{-6+4}{2} ,\frac{3+7}{2} )\\Midpoint=(\frac{-2}{2} ,\frac{10}{2} )\\Midpoint=(-1 ,5)$

So, we get Midpoint (x,y)=(-1,5)

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Radius of circle can be found by first finding diameter using distance formula and then divide it by 2.

$Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\Distance=\sqrt{(4-(-6))^2+(7-3)^2} \\Distance=\sqrt{(4+6)^2+(7-3)^2} \\Distance=\sqrt{(10)^2+(4)^2} \\Distance=\sqrt{100+16}\\Distance=\sqrt{116}\\Distance = 10.77$

So, Diameter = 10.77

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Equation of circle having centre(-1,5) and radius r = 5.38 is:

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