Question

X to the second-8x+7=0

Answer 1

Answer to this equation is x=1 and x=6 Im not to sure!

Answer 2

If your'e looking to complete the square, then here's how you do it:
1.) Subtract 7 from each side: $x^{2} -8x=-7$
2.) Take half of the value of B, which is 4, then square it to get C
3.) Now you should have $x^{2} -8x+(4)^2=-7+(4)^2$, because what you do to one side you have to do to the other
4.) Take the value of $x^{2}$ and 4, and plug them into an ordered pair: $(x-4)^2=9$
Now take the square root of both sides which is equal to $x-4=$±$3$
5.) Now subtract 4 from each side to isolate x: $x=4$±3
6.) Solve: $x=4-3$ & $x=4+3$
Final Answer: $x=1$ & $x=7$
Hope this helps!!