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3 years ago

X to the second-8x+7=0

Mathematics

2 answers:

guajiro [1.7K]3 years ago

7 0

Answer to this equation is x=1 and x=6 Im not to sure!

Rufina [12.5K]3 years ago

4 0

If your'e looking to complete the square, then here's how you do it:
1.) Subtract 7 from each side: $x^{2} -8x=-7$
2.) Take half of the value of B, which is 4, then square it to get C
3.) Now you should have $x^{2} -8x+(4)^2=-7+(4)^2$ , because what you do to one side you have to do to the other
4.) Take the value of $x^{2}$ and 4, and plug them into an ordered pair: $(x-4)^2=9$
Now take the square root of both sides which is equal to $x-4=$ ± $3$
5.) Now subtract 4 from each side to isolate x: $x=4$ ±3
6.) Solve: $x=4-3$ & $x=4+3$
Final Answer: $x=1$ & $x=7$
Hope this helps!!

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Which two values of x are roots of the polynomial below? x^2-3x+5

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Given:

Polynomial $x^2-3x+5$

To find:

The values of x.

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$x^2-3x+5=0$

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Substitute the values in the formula, we get

$$x=\frac{-(-3) \pm \sqrt{(-3)^{2}-4 \cdot 1 \cdot 5}}{2 \cdot 1}$

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$$x=\frac{3 \pm \sqrt{-11}}{2}$

$$x=\frac{3 - \sqrt{-11}}{2} \ \text{and} \ x=\frac{3 + \sqrt{-11}}{2}$

Option E and option F are the roots of the polynomial.

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3 years ago

Find the range of the function F(x) = the integral from 0 to x of the square root of 4-t^2 dt

ioda

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On the opposite end, if x = -2, then the integral has the same value, but the integral from 0 to -2 is equal to the negative integral from -2 to 0. So the minimum value is -π.

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2 years ago

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3 years ago

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Answer:

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2 years ago

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3 years ago