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3 years ago

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A parabola is represented by the equation y = x2 + 6x − 17. The x-intercepts of the parabola are and_ . The y-intercept

of the parabola is______ . (If necessary, round your answers to the nearest hundredth.)

2 answers:

brilliants [131]3 years ago

7 0

Answer:

x-intercepts : $(-3+\sqrt{26} ,0),(-3-\sqrt{26} ,0)$ ≈ $(2.09,0), (-8.09,0)$

y- intercepts : $(0,-17)$

Step-by-step explanation:

To find the x-intercept(s), substitute in 0 for y and solve for x.

thus

$x^{2} + 6x-17=0$

Using quadratic formula for finding value of x.

$x=\frac{-b}{2a}$ ± $\frac{\sqrt{b^{2}-4ac} }{2a}$

thus we get,

x-intercepts : $(-3+\sqrt{26} ,0),(-3-\sqrt{26} ,0)$ ≈ $(2.09,0), (-8.09,0)$

Now for y-intercept(s), substitute in 0 for x and solve for y.

thus

$y = x^{2} + 6x-17$

$y = (0)^{2} + 6(0)-17$

$y =-17$

we get,

y- intercepts : $(0,-17)$

kramer3 years ago

4 0

Answer:

2.8, 8.8, and -17 respectively.

Step-by-step explanation:

We need to find roots of the equation.

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