Question

A parabola is represented by the equation y = x2 + 6x − 17. The x-intercepts of the parabola are____ and_____ . The y-intercept of the parabola is______ . (If necessary, round your answers to the nearest hundredth.)

Answer 1

Answer:

x-intercepts : $(-3+\sqrt{26} ,0),(-3-\sqrt{26} ,0)$ ≈ $(2.09,0), (-8.09,0)$

y- intercepts : $(0,-17)$

Step-by-step explanation:

To find the x-intercept(s), substitute in  0 for y and solve for x.

thus

                         $x^{2} + 6x-17=0$

Using quadratic formula for finding value of x.

                            $x=\frac{-b}{2a}$ ± $\frac{\sqrt{b^{2}-4ac} }{2a}$

thus we get,

   x-intercepts :  $(-3+\sqrt{26} ,0),(-3-\sqrt{26} ,0)$ ≈ $(2.09,0), (-8.09,0)$

Now for y-intercept(s), substitute in 0 for x and solve for y.

thus

                            $y = x^{2} + 6x-17$

                           $y = (0)^{2} + 6(0)-17$

                            $y =-17$

we get,

                  y- intercepts : $(0,-17)$

Answer 2

Answer:

2.8, 8.8, and -17 respectively.

Step-by-step explanation:

We need to find roots of the equation.