2 years ago

100 points whats 9 times 3 plus 3 divided by 2

Mathematics

2 answers:

otez555 [7]2 years ago

7 0

Answer:

Step-by-step explanation:

Dmitrij [34]2 years ago

5 0

Answer:

Step-by-step explanation:

28.5

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EleoNora [17]

Start by multiplying each side of the inequality by $\sqrt{x + 1}$ and simplifying:

$2 \sqrt x + \frac{1}{\sqrt{x+1}} \leq 2 \sqrt{x + 1}$
$(2 \sqrt x + \frac{1}{\sqrt{x+1}})(\sqrt{x + 1}) \leq (2 \sqrt{x + 1})(\sqrt{x + 1})$
$2 \sqrt{x(x + 1)} + 1 \leq 2(x + 1)$
$2 \sqrt{x^2 + x} + 1 \leq 2x + 2$
$2 \sqrt{x^2 + x} \leq 2x + 1$
$\sqrt{x^2 + x} \leq x + \frac{1}{2}$

From here, we can square both sides to get

$x^2 + x \leq (x + \frac{1}{2})^2$
$x^2 + x \leq x^2 + x + \frac{1}{4}$
$0 \leq \frac{1}{4}$ , which is always true.

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2 years ago

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crimeas [40]

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Step-by-step explanation:

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2 years ago

Evaluate the expression for = −3 and = 5.<br><br> r^{-4} s^2

Butoxors [25]

If r = -3 and s = 5:
(r^-4)(s^2) = (-3^-4)(5^2) = (1/81)(25) = 25/81

If r = 5 and s = -3:
(r^-4)(s^2) = (5^-4)(3^2) = (1/625)(9) = 9/625

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2 years ago

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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3 years ago

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