Answer:
(x²/4) + (y²/16) ≤ 1
Step-by-step explanation:
The general form of the ellipse in the graph is
x²/4 + y²/16 = 1
we want to find the inequality which represents the shaded area this will determine whether which of the following 2 choices are correct
Choice 1: x²/4 + y²/16 ≥ 1
Choice 2: x²/4 + y²/16 ≤ 1
we note that point (0,0) lies inside the shaded area. Which means if we substitute (0,0), it should create an equality that is valid.
try choice 1: 0²/4 + 0²/16 = 0 ≥ 1 (not valid because obviously zero is smaller than 1)
try choice 1: 0²/4 + 0²/16 = 0 ≤ 1 (this is valid, hence choice 2 is the answer)
So you divide 50 by 2 so there are 25 before him
BE and CD are parallel, so the triangles ABE and ACD are similar. Then the following relation holds:
AE/AD = AB/AC
10/(10 + 8) = x/(x + 6)
Solve for x :
10 (x + 6) = x (10 + 8)
10x + 60 = 18x
8x = 60
x = 60/8 = 7/5
The answer is 3, if it is in square meters it must be a square therefore each side is the same length
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