Answer:
Redundancy is the mechanism that occurs in database's data as the same data is stores in the multiple location.It creates repeated data by accident or for backup purpose.
The issues that arise due to the redundancy of the data is the storage space in database gets consumed and thus wastes the space in storing information in multiple locations.When any update occurs in the stored data's field value , it also has to be changed in the multiples occurrences.
Answer:
No for GOTO
Yes for Pointer
Explanation:
<u>GOTO statement</u>
This declaration is used to pass control to the program's marked declaration. The label is the valid identifier and is positioned just before the declaration from which the control is transmitted.
It becomes hard to trace a program's control flow, making it hard to comprehend the program logic. Any program in C language can be written without using a GOTO statement.
<u>Pointers</u>
A C # pointer is nothing but a variable holding another type of memory address. However, in C # pointer only the memory address of the value types and arrays can be declared.
C # supports pointers to a restricted extent. Unlike reference kinds, the default trash collection system does not track pointer kinds. Pointers are not allowed to point to a type of structure containing a type of reference or a type of reference.
During the garbage collection process, the C #garbage collector can move objects in memory as they wish. The C #offers a unique fixed keyword for telling Garbage Collector not to move an item. This implies that the place of the value kinds referred to is fixed in memory. This is called pinning in C #.
I believe the answer you are looking for is C. :)
Answer:
24:36 if you want it in the smallest form it is 2:3
Answer:
The program in Python is as follows:
wordInput = input()
myList = wordInput.split(" ")
for i in myList:
print(i,myList.count(i))
Explanation:
This gets input for the word
wordInput = input()
This splits the word into a list using space as the delimiter
myList = wordInput.split(" ")
This iterates through the list
for i in myList:
Print each word and its count
print(i,myList.count(i))
