Question

Given a sorted list of integers, output the middle integer. assume the number of integers is always odd.

Answer 1

integer userInput

integer i

integer mid

integer array(20) number

userInput = 1

for i = 0; userInput >= 0; i = i + 1

  if number[i] > -1

     userInput = Get next input

     number[i] = userInput

i = i - 1

mid = i / 2

if i > 9

  Put "Too many inputs" to output

elseif i % 2 == 0

  Put number[mid - 1] to output

else

  Put number[mid] to output