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zalisa [80]
3 years ago
5

R=p/4(c+k) for k, please help, thank you!

Mathematics
1 answer:
White raven [17]3 years ago
8 0

Answer:

k=\frac{-cp+4r}{p}

Step-by-step explanation:

r=p/4(c+k)

\frac{r}{p/4} =c+k

\frac{r}{p/4} -c=k

-cp+4r=kp

\frac{-cp+4r}{p} =k

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Pls help!!! thank you in advance​
Oliga [24]

answer simple

i thinks its b

5 0
3 years ago
Read 2 more answers
There are 7 red candies in a pack, 9 blue candies in a pack, and 12 pink candies in a pack. If your wonderful math teacher wants
pentagon [3]
Given:
7 red candies
9 blue candies
12 pink candies

Condition:
Number of bags that has equal number of candies.

We can do 7 bags with 1 colored candy each. There will be an excess of 2 blue candies and 5 pink candies.

We can do 4 bags with 1 red candy, 2 blue candies, 3 pink candies. There will be an excess of 3 red candies and 1 blue candy.

We can do 3 bags with 2 red candies, 3 blue candies, 4 pink candies. There will be an excess of 1 red candy.
5 0
3 years ago
Which of the following is equivalent to (2x+3)(x-7)?
maw [93]
I’m pretty sure it’s it’s between f and g. Sorry if I’m not exact but hope this helps
8 0
3 years ago
30 POINTS!!! PLEASE HELP ME
Ludmilka [50]

Remark

All you need is 2 points to get the line of the equation. One is itself (B and B') is the same in both triangles. Now we need to find one more point. Since this is a reflection, the midpoint between C and C' is the second point. That choice of C and C' is completely arbitrary.

Step One

y intercept of the line. That point is B which is (0,1)

Step Two

Find the midpoint between C and C'

C is (-4,-2) and C' is ( 0 , - 4) The midpoint is

C" = (x2 + x1)/2 , (y2 + y1)/2

C" = (-4 + 0 )/2 , (-2 + - 4) / 2

C" = (-4)/2 , - 6/2

C" = (-2, - 3) C" is the midpoint between C and C'

Step 3

Find the equation of the line.

y = ax + b We are trying to find A

y = ax + 1

-3 = a(-2) + 1

-3 - 1 = a(-2)

- 4 = a(-2) Divide by -2

-4/-2 = a

a = 2

The slope of the line is 2

Answer

y = 2x + 1

6 0
3 years ago
May I know the values of x and y of the following equation?<br>(5-3i)(x-yi) = 3(x+2yi)+1-2i​
gogolik [260]

Answer:

  (x, y) = (17/31, 1/31)

Step-by-step explanation:

Simplify the given equation, then equate real parts and equate imaginary parts. This will give you two equations in the two unknowns.

__

<h3>simplify</h3>

  (5 -3i)(x -yi) = 3(x +2yi) +1 -2i

 5x -5yi -3xi +3yi² = 3x +6yi +1 -2i

  (5x -3y) +i(-5y -3x) = (3x +1) +i(6y -2)

<h3>equate real, imaginary parts</h3>

This resolves to the two equations ...

  • 5x -3y = 3x +1
  • -5y -3x = 6y -2
<h3>solve the system</h3>

Putting these equations into general form gives ...

  2x -3y -1 = 0

  3x +11y -2 = 0

Using the "cross multiplication method" to solve these equations, we get ...

  x = ((-3)(-2) -(11)(-1))/(2(11) -3(-3)) = 17/31

  y = ((-1)(3) -(-2)(2))/31 = 1/31

The values of x and y that satisfy this equation are ...

  (x, y) = (17/31, 1/31)

_____

You can read more about the cross multiplication method here.

brainly.com/question/26397343

3 0
2 years ago
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