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3 years ago

The legs of a right triangle measure 5√2 cm and 4√2 cm. Find the area.

Mathematics

2 answers:

lianna [129]3 years ago

4 0

The area of right triangle=1/2*leg1*leg2=20 cm2

Eduardwww [97]3 years ago

3 0

Area of a triangle = 1/2 × 1st leg × 2nd leg
A = 1/2 × 5√2 × 4√2
A = 1/2 × 20×2
A = 20 cm²

In short, Your Answer would be 20 cm²

Hope this helps!

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What's 149 rounded to the nearest tenth

alexandr1967 [171]

150 because you round the 4 because the number in the ones place is over 5.

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3 years ago

Ed's new car has a value of $23,500, but it is expected to depreciate at a rate of 7.5% per year. What is the value of Ed's car

Kazeer [188]

Answer:

$13,616

Step-by-step explanation:

For each year we will have to constantly decrease it by 7.5%

23,500 - 7.5%

= 21,737.5

= 21,737.5 - 7.5%

= 20,107.1875

= 20,107.1875 - 7.5%

= 18599.1484375

= 18599.1484375 - 7.5%

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Definitively we will get the answer $13,616

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3 years ago

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3 years ago

United Flight 15 from New York's JFK airport to San Francisco uses a Boeing 757-200 with 182 seats. Because some people with res

Tcecarenko [31]

Answer:

There is a 29.27% probability that the flight is overbooked. This is not an unusually low probability. So it does seem too high so that changes must be made to make it lower.

Step-by-step explanation:

For each passenger, there are only two outcomes possible. Either they show up for the flight, or they do not show up. This means that we can solve this problem using binomial distribution probability concepts.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And $\pi$ is the probability of X happening.

A probability is said to be unusually low if it is lower than 5%.

For this problem, we have that:

There are 200 reservations, so $n = 200$ .

A passenger consists in a passenger not showing up. There is a .0995 probability that a passenger with a reservation will not show up for the flight. So $\pi = 0.0995$ .

Find the probability that when 200 reservations are accepted for United Flight 15, there are more passengers showing up than there are seats available.

X is the number of passengers that do not show up. It needs to be at least 18 for the flight not being overbooked. So we want to find $P(X < 18)$ , with $\pi = 0.0995, n = 200$ . We can use a binomial probability calculator, and we find that:

$P(X < 18) = 0.2927$ .

There is a 29.27% probability that the flight is overbooked. This is not an unusually low probability. So it does seem too high so that changes must be made to make it lower.

5 0

2 years ago

The condition_______?proves that ∆ABC and ∆EFG are congruent by the SAS criterion.

snow_lady [41]

Answer:

(1) D.Angle C is congruent to to Angle F. (2) C. SSS. (3) C. cannot be congruent to.

Step-by-step explanation:

From the given figure it is noticed that

$AC=EG$

$CB=GF$

According to SAS postulate, if two sides and the included angle of one triangle are congruent to two sides and the included angle of another triangle, then both triangles are congruent.

The included angles of congruent sides are angle C and angle G.

So, condition "Angle C is congruent to to Angle F" will prove that the ∆ABC and ∆EFG are congruent by the SAS criterion.

If $AB\neq EF$

According to SSS postulate, if all three sides in one triangle are congruent to the corresponding sides in the other.

Since two corresponding sides are congruent but third sides of triangles are not congruent, therefore SSS criterion for congruence is violated.

Since two corresponding sides are congruent but third sides of triangles are not congruent, therefore the included angle of congruent sides are different.

$\angle C\neq \angle G$

Therefore angle C and angle F cannot be congruent to each other.

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3 years ago