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2 years ago

Simplify the expression below. x4 • x4 • x4

Mathematics

1 answer:

beks73 [17]2 years ago

5 0

Answer:

x^12.

Step-by-step explanation:

x^4 times x^4 times x^4.

Since we don't know x and the 4's are exponents we just add them together.

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Hey What is -5t > 10

yanalaym [24]

Answer: 10 (ten) is an even number

following 9 and preceding 11

Step-by-step explanation:

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2 years ago

Under the best conditions, a sprout has a 40% probability of blooming.if two sprouts are selected at random, what is the probabi

Minchanka [31]

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2 years ago

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Kelly purchased 5 containers of ice cream for a party. Each container holds 8 cups of ice cream. Before the party, her brother a

victus00 [196]

Given:

Kelly purchased 5 containers of ice cream for a party.

Each container holds 8 cups of ice cream.

Her brother ate 2 cups of ice cream.

One serving of ice cream = 2/3 of a cup.

To find:

Number of servings of ice cream will be left for the party?

Solution:

We have,

1 container = 8 cups of ice cream

5 containers = 5×8 = 40 cups of ice cream

Her brother ate 2 cups of ice cream. So, remaining cups of ice cream is

$40-2=38$ cups

Now,

$\dfrac{2}{3}$ of a cup = 1 serving

1 cup = $\dfrac{3}{2}$ serving

38 cup = $38\times \dfrac{3}{2}$ serving

= $19\times 3$ serving

= 57 serving

Therefore, 57 servings of ice cream will be left for the party.

4 0

2 years ago

Can somebody prove this mathmatical induction?

Flauer [41]

Answer:

See explanation

Step-by-step explanation:

1 step:

n=1, then

$\sum \limits_{j=1}^1 2^j=2^1=2\\ \\2(2^1-1)=2(2-1)=2\cdot 1=2$

So, for j=1 this statement is true

2 step:

Assume that for n=k the following statement is true

$\sum \limits_{j=1}^k2^j=2(2^k-1)$

3 step:

Check for n=k+1 whether the statement

$\sum \limits_{j=1}^{k+1}2^j=2(2^{k+1}-1)$

is true.

Start with the left side:

$\sum \limits _{j=1}^{k+1}2^j=\sum \limits _{j=1}^k2^j+2^{k+1}\ \ (\ast)$

According to the 2nd step,

$\sum \limits_{j=1}^k2^j=2(2^k-1)$

Substitute it into the $\ast$

$\sum \limits _{j=1}^{k+1}2^j=\sum \limits _{j=1}^k2^j+2^{k+1}=2(2^k-1)+2^{k+1}=2^{k+1}-2+2^{k+1}=2\cdot 2^{k+1}-2=2^{k+2}-2=2(2^{k+1}-1)$

So, you have proved the initial statement

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3 years ago

HeLP WiLL gIve BranIliEST

mario62 [17]

I tried just give it to me anyway

7 0

1 year ago

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