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lara31 [8.8K]
3 years ago
5

Write an expression that is equivalent to (4x + 9)

Mathematics
2 answers:
notka56 [123]3 years ago
6 0
The final answer would be 4x+9.
zalisa [80]3 years ago
4 0
As this is already in its simplest form, I believe the only other expression is 4*X +9
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Can you organize collections of numbers into mathematical sets?
Bezzdna [24]
Yes by 10's and hundreds and ones place and even and odd. And pine and composite
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¿cuál es el número que no pertenece a esta suceción 99,105111,117,123,129,135,141,147,153
shepuryov [24]

No hay ninguno de los nimbers que no pertenezca a la secuencia.

<h3>¿Qué número no pertenece a la secuencia?</h3>

Sabemos que una secuencia tiene que ver con un arreglo de números en un orden definido. Todos los números en una secuencia deben tener la misma razón común o diferencia común.

Si miramos todos los números que están escritos en la secuencia, la diferencia común aquí es seis. Se sigue entonces que todos los números son parte de la sucesión y no hay ninguno de los números que no pertenezca a la sucesión.

Obtenga más información sobre la secuencia: brainly.com/question/21961097

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2 years ago
The play started at 2:10 p.m and ended at 3:22 p.m How long did the play last?
hodyreva [135]
1 hour and 12 minutes
8 0
3 years ago
Read 2 more answers
Let V be the event that a computer contains a virus, and let W be the event that a computer contains a worm. Suppose P(V) = 0.17
ArbitrLikvidat [17]

Answer: 0.82

Step-by-step explanation:

The probability of the computer not containing neither a virus nor a worm is expressed as P(V^{C}∩W^{C}) , where P(V^{C}) is the probability that the event V doesn't happen and P(W^{C}) is the probability that the event W doesn't happen.

P(V^{C})= 1-P(V) = 1-0.17 = 0.83

P(W^{C})=1-P(W) = 1-0.05 = 0.95

Since V^{C} and W^{C} aren't mutually exclusive events, then:

P(V^{C}∪W^{C}) = P(V^{C}) + P(W^{C}) - P(V^{C}∩W^{C})

Isolating the probability that interests us:

P(V^{C}∩W^{C})= P(V^{C}) + P(W^{C}) - P(V^{C}∪W^{C})

Where P(V^{C}∪W^{C}) = 1 - 0.04 = 0.96

Finally:

P(V^{C}∩W^{C}) = 0.83 + 0.95 - 0.96 = 0.82

5 0
3 years ago
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barxatty [35]

Answer:

The ones 1 1/12, 1/12, 10 1/3, and 1 1/9, all go in the less than 10 1/2. And three numbers marked 10 1/2 go in the greater than 10 1/2

Step-by-step explanation:

7 0
3 years ago
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