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3 years ago

Pls I'm really confused

Mathematics

1 answer:

aniked [119]3 years ago

8 0

Would it be 3x times as far and the second answer 2x as far

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A bucket holds b liters of water. But a jar holds 8 fewer liters than the bucket. How many times can the bucket hold than the ja

kykrilka [37]

Answer:

b / (b - 8)

Step-by-step explanation:

Given that :

Litres of water held by bucket = b

Jar holds 8 litres fewer than bucket; hence, litres held by jar = b - 8

The number of times bucket can hold than jar is :

Litres held by bucket / litres held by jar

b / (b - 8)

8 0

3 years ago

How do you compare y-intercepts and rates of change

Sphinxa [80]

Not really sure what you mean by compare. The only thing I can think of is the y intercept is generally a good point to start from to count the rise/run

5 0

3 years ago

What is the maximum number of snowmen they can make?

Anastasy [175]

To answer this question, you do 5 2/3 divided by 1/2. First, change 5 2/3 to 17/3. Then, use the reciprocal method by doing 17/3 times 2/1, which gives you 34/3. That’s 11.3 repeating, so they can make 11 whole snowmen.

3 0

3 years ago

I need help please!!!!

nika2105 [10]

Answer: I think it is 364.80

5 0

3 years ago

What are the endpoint coordinates for the midsegment of △BCD that is parallel to BC?

natulia [17]

Answer:

<em>The endpoint coordinates for the mid-segment are: $(-2,-1)$ and $(1,0)$ </em>

Step-by-step explanation:

According to the given diagram, the coordinates of the vertices of $\triangle BCD$ are: $B(-3,1), C(3,3)$ and $D(-1,-3)$

Now, the endpoints of the mid-segment of $\triangle BCD$ which is parallel to $BC$ will be the mid-points of sides $BD$ and $CD$ .

<u>Formula for the coordinate of mid-point</u> : $(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2})$ , where $(x_{1}, y_{1})$ and $(x_{2}, y_{2})$ are two endpoints.

So, the mid-point of $BD$ will be: $(\frac{-3-1}{2},\frac{1-3}{2})=(\frac{-4}{2},\frac{-2}{2})=(-2,-1)$

and the mid-point of $CD$ will be: $(\frac{3-1}{2},\frac{3-3}{2})=(\frac{2}{2},\frac{0}{2})=(1,0)$

Thus, the endpoint coordinates for the mid-segment of $\triangle BCD$ that is parallel to $BC$ are $(-2,-1)$ and $(1,0)$

4 0

3 years ago

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