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Fynjy0 [20]
3 years ago
5

Find 250% of 60 please help thanks

Mathematics
1 answer:
____ [38]3 years ago
4 0

Answer:

the answer is 150!

Step-by-step explanation:

250% of 60=150

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For questions 1 and 2, multiple answers may be selected
d1i1m1o1n [39]

The discrete data is (b) while the continuous data are (a) and (d)

<h3>What are discrete data?</h3>

These are data that can be represented using positive whole numbers.

Using the above definition as a guide, the discrete data is (b) The number of books in your apartment

<h3>What are continuous data?</h3>

These are data that can be represented using decimal numbers.

Using the above definition as a guide, the continuous data are (a) The weight of cows  and (d) The ounces of water that you drink each day

Read more about discrete data at:

brainly.com/question/4811422

#SPJ1

6 0
2 years ago
What grade is 92% out of 115
KatRina [158]
To calculate this, we need to do the following:

92 * 115 = 10580 (we first multiply the percentage with our number)
 
10580 / 100 = 105.8 (and divide what we get by 100 to get the final answer)

And this is also already the answer: 105.8
5 0
3 years ago
Don’t know much about geometry
Mariana [72]

Answer:

Step-by-step explanation:

J is a tangent to the circle and it is at right angle,

So applying Pythagorean theorem

HK² = KJ² + HJ²

HK² = 8²+ 15²

HK² = 64 + 225

HK² = 289

HK = √289

HK = 17 mi

7 0
3 years ago
Any one who needs help friend me okay?
artcher [175]

Answer:

i dont know you

Step-by-step explanation:

who are you

8 0
3 years ago
Read 2 more answers
If the acceleration of an object is given by dv/dt = −2v, Find the position function s(t) if v(0) = 7 and s(0) = 0.
kirill [66]

Answer:

Step-by-step explanation:

Given that acceleration of an object is

\frac{dv}{dt} =-2v\\\frac{dv}{v} =-2dt\\ln v = -2t+C\\

is the solution to the differential equation

Since v(0) =7

we get ln 7 = C

Hence lnv = -2t+ln 7\\v=7e^{-2t}

since velocity is rate of change of distance s we have

v=\frac{ds}{dt} =7e^{-2t}\\s= [tex]s(t) =\frac{-7}{2} (e^{-2t})+C)[

substitute t=0 and s=0

C=7/2

So solution for distance is

s(t) =\frac{-7}{2} (e^{-2t}-1)

4 0
4 years ago
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