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Mathematics

1 answer:

andrew11 [14]2 years ago

6 0

I think 5?
These are the ages,

12, 12, 14, 15, 17,
28, 29,
40, 41, 44, 45,
50,
69

Only the people on the first row are under 19 and there are 5 people.

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What is the probability each player has a winning?

olganol [36]

You have a 1 in 50 chance (ie A)
Explanation:
Let's start with the first bag. In it sits 5 numbers. So, you have a 1 in 5 chance that the number picked will be yours.

Now, let's consider the second bag. You have 10 different numbers and only one of yours may be picked. Hence, you have a 1 in 10 chance that yours will get picked.

Since we want them simultaneously, we will need to multiply the two probabilities together, yielding a 1 in 50 chance.

4 0

2 years ago

Really need help guys!<br> Love you if you can solve them wiz steps!!!!

Marta_Voda [28]

Answer:

Step-by-step explanation:

$x^2+y^2-8x+4y+4=0\\\\a)\\\\x^2-8x+y^2+4y+4=0\\\\x^2-2*x*4+(y^2+2*y*2+2^2)=0\\\\x^2-2*x*4+4^2+(y+2)^2=4^2\\\\(x-4)^2+(y+2)^2=4^2\\$

Hence,

The radius of the circle is 4 units, coordinates of its centre are (4,-2).

$b)\\\\y=0\\x^2+0^2-8x+4*0+4=0\\x^2-8x+4=0\\a=1\ \ \ \ b=-8\ \ \ \ c=4\\D=(-8)^2-4*1*4\\D=64-14\\D=48\\\sqrt{D}=\sqrt{48} \\ \sqrt{D}=\sqrt{16*3} \\\sqrt{D}=\sqrt{4^2*3} \\\sqrt{D}=4\sqrt{3} \\\displaystyle\\x=\frac{-(-8)б4\sqrt{3} }{2*1} \\\\x=\frac{8б4\sqrt{3} }{2} \\x_1=4-2\sqrt{3} \\x_2=4+2\sqrt{3}$

$c)\\\\A(6,2\sqrt{3}-2)\\ (x-4)^2+(y+2)^2=4^2\\(6-4)^2+(2\sqrt{3} -2+2)^2=16\\2^2+(2\sqrt{3} )^2=16\\4+2^2*(\sqrt{3})^2=16\\ 4+4*3=16\\4+12=16\\16\equiv16$