SOMEONE HELP ME PLEASE

There are three possible cases:

A) No triangles are able to be formed
B) Exactly one triangle can be formed
C) Exactly two triangles can be formed

Because of this, you cannot use SSA to prove triangle congruence.

5 0

4 years ago

The longest side of an isosceles triangle is 11 cm less than twice as long as the other sides. The perimeter of the triangle is

lana66690 [7]

Answer:

15 cm, 15 cm, and 19 cm

Step-by-step explanation:

Isosceles Triangle is a type of triangle in which two of the three sides are equal in length. The perimeter is 49 cm. Therefore, in this question, since the sides are unknown, we can assume that:

Length of the longer side = x cm.

Length of the other sides = y cm.

The relationship between x and y is given by:

x = (2y - 11) cm (because it is mentioned that the longest side is 11 cm less than twice as long as the other sides).

Perimeter of a triangle = sum of all sides.

Since its an isosceles triangle, therefore:

Perimeter of the triangle = x + 2y.

Substituting the values in the perimeter formula gives:

Perimeter of the triangle = 2y - 11 + 2y.

49 = 4y - 11.

4y = 60.

y = 15 cm.

Substituting y = 15 in the equation x = 2y - 11 gives x = 2(15) - 11 = 19 cm.

So in the ascending order, the lengths are 15 cm, 15 cm, and 19 cm!!!

5 0

3 years ago

Solve using the quadratic formula 2x^2+x+67=0

telo118 [61]

Answer:

$\displaystyle x=\frac{-1 \pm i\sqrt{535}}{2}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Multiple Roots
Standard Form: ax² + bx + c = 0
Quadratic Formula: $\displaystyle x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$

Algebra II

Imaginary Root i = √-1

Step-by-step explanation:

Step 1: Define

Identify

2x² + x + 67 = 0

a = 2

b = 1

c = 67

Step 2: Solve for x

Substitute in variables [Quadratic Formula]: $\displaystyle x=\frac{-1 \pm \sqrt{1^2-4(2)(67)}}{2(1)}$
Multiply: $\displaystyle x=\frac{-1 \pm \sqrt{1^2-4(2)(67)}}{2}$
[√Radical] Evaluate exponents: $\displaystyle x=\frac{-1 \pm \sqrt{1-4(2)(67)}}{2}$
[√Radical] Multiply: $\displaystyle x=\frac{-1 \pm \sqrt{1-536}}{2}$
[√Radical] Subtract: $\displaystyle x=\frac{-1 \pm \sqrt{-535}}{2}$
[√Radical] Simplify: $\displaystyle x=\frac{-1 \pm i\sqrt{535}}{2}$

3 0

3 years ago