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Anni [7]
3 years ago
10

What is 3d − 7d + 2.8 < 5.8 − 27

Mathematics
1 answer:
weqwewe [10]3 years ago
3 0
3d -7d+ 2.8 < 5.8 -27
⇒ -4d+ 2.8 < 5.8 -27
⇒ -4d < 5.8 -27 -2.8
⇒ -4d < -24
⇒ d > (-24)/(-4)
⇒ d > 6

Final answer: d > 6~
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The measurement of an angle is five times the measurement of its supplement.What is the measurement of the angle? Is it 30°, 35°
choli [55]

Two angles that are supplements add up to 180°.

"The angle" is five times its supplement.

If I call the supplement 'S', then 'the angle' = 5S .

                                       S + 5S  =  180°

Combine like terms:      6S  =  180°

Divide each side by  6 :  S  =  30°

The supplement of 'the angle' = 30°.
That's one of the choices.

"The angle" = 5S  =  150°.
That's NOT one of the choices.

6 0
3 years ago
Consider the experiment of rolling two standard (six-sided) dice and taking their sum. Assume that each die lands on each of its
Strike441 [17]

Answer:

36

Step-by-step explanation:

Given that:

2 standard six sided dice are rolled :

Die 1 = 1, 2, 3, 4, 5, 6

Die 2 = 1, 2, 3, 4, 5, 6

Outcome = ordered pair of Number on the two dice

Event = different sum of the ordered pair of numbers.

The number of outcomes in the experiment = the sample space =) number of Faces)^number of dies

= 6^2

= 36 different outcomes

7 0
3 years ago
Dennis, Emily, and Fernando want to find the zeros of the polynomial p(x)=x3+6x2+9x. Each student worked independently and prese
alexandr402 [8]

Answer:

  • Fernando’s response is incorrect because he inappropriately applied the Rational Root Theorem.
  • Dennis’ response is incorrect. According to the Fundamental Theorem of Algebra, the polynomial p(x) cannot have six roots, or zeros, because it is only of degree 3.
  • Emily’s response is correct because she correctly factored the polynomial, and correctly used the definition of zeros to reach her answer.

Step-by-step explanation:

The Rational Root Theorem offers a list of possible rational roots. Each needs to be tested to see if it is an actual rational root. Fernando and Dennis made inappropriate assumptions about what the Rational Root Theorem allowed them to conclude.

3 0
3 years ago
Intersection point of Y=logx and y=1/2log(x+1)
GalinKa [24]

Answer:

The intersection is (\frac{1+\sqrt{5}}{2},\log(\frac{1+\sqrt{5}}{2}).

The Problem:

What is the intersection point of y=\log(x) and y=\frac{1}{2}\log(x+1)?

Step-by-step explanation:

To find the intersection of y=\log(x) and y=\frac{1}{2}\log(x+1), we will need to find when they have a common point; when their x and y are the same.

Let's start with setting the y's equal to find those x's for which the y's are the same.

\log(x)=\frac{1}{2}\log(x+1)

By power rule:

\log(x)=\log((x+1)^\frac{1}{2})

Since \log(u)=\log(v) implies u=v:

x=(x+1)^\frac{1}{2}

Squaring both sides to get rid of the fraction exponent:

x^2=x+1

This is a quadratic equation.

Subtract (x+1) on both sides:

x^2-(x+1)=0

x^2-x-1=0

Comparing this to ax^2+bx+c=0 we see the following:

a=1

b=-1

c=-1

Let's plug them into the quadratic formula:

x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

x=\frac{1 \pm \sqrt{(-1)^2-4(1)(-1)}}{2(1)}

x=\frac{1 \pm \sqrt{1+4}}{2}

x=\frac{1 \pm \sqrt{5}}{2}

So we have the solutions to the quadratic equation are:

x=\frac{1+\sqrt{5}}{2} or x=\frac{1-\sqrt{5}}{2}.

The second solution definitely gives at least one of the logarithm equation problems.

Example: \log(x) has problems when x \le 0 and so the second solution is a problem.

So the x where the equations intersect is at x=\frac{1+\sqrt{5}}{2}.

Let's find the y-coordinate.

You may use either equation.

I choose y=\log(x).

y=\log(\frac{1+\sqrt{5}}{2})

The intersection is (\frac{1+\sqrt{5}}{2},\log(\frac{1+\sqrt{5}}{2}).

6 0
2 years ago
Which symbol makes the comparisons true ? Complete the comparison -6 ? 3
Usimov [2.4K]
<h3>Hello!</h3>

======================================

Negative numbers are always less than positive ones.

Do you remember the symbol for "less than"? That's right, "<" :)

Hence,

-6<3

Because

-6 is negative (the - sign tells us that)

3 is positive

===================================

<h3>Notes:</h3>
  • Hope everything is clear.
  • Let me know if you have any questions!
<h3>Answered by:</h3>

~DiamondS~

6 0
1 year ago
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