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Anestetic [448]

3 years ago

12

A price p (in dollars) and demand x for a product are related by

1 answer:

Leni [432]3 years ago

7 0

<span>Plugging in p = 10 to solve for x:

x^2-50x-600 = (x-60)(x+10) = 0 => x = 60
x^2 - 5xp + 50p^2 = 3100

Differentiate with respect to time,

2xx' - 50x'p - 50xp' + 100pp' = 0
240 - 100(10) - 3000p' + 1000p' = 0

p' = -.38

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
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3. How much simple interest is earned on $6,000 at an interest rate of 4.25% in 4.5 years?

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3 years ago

A/-6 + 8 = 12. a = <br>Please help!!! Thanks so much! <br><br>~kweenie~

irina [24]

Answer:

a = -24

Step-by-step explanation:

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8 0

3 years ago

What is the true solution to the equation below? 2 in e in2×-in e in 10×= in 30 A x=30 B x=75 C x=150 D x=300

hodyreva [135]

Answer:

Option B.

Step-by-step explanation:

Let as consider the given equation:

$2\ln e^{\ln 2x}-\ln e^{\ln 10x}=\ln 30$

It can be written as

$2(\ln 2x)-(\ln 10x)=\ln 30$ $[\because \ln e^a=a]$

$\ln (2x)^2-(\ln 10x)=\ln 30$ $[\because \ln a^b=b\ln a]$

$\ln \dfrac{4x^2}{10x}=\ln 30$ $[\because \ln \dfrac{a}{b}=\ln a-\ln b]$

$\ln \dfrac{2x}{5}=\ln 30$

On comparing both sides, we get

$\dfrac{2x}{5}=30$

Multiply both sides by 5.

$2x=150$

Divide both sides by 2.

$x=75$

Therefore, the correct option is B.

7 0

3 years ago