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AysviL [449]
3 years ago
7

Solve 2x + 5m = 2y - 4x for y.

Mathematics
2 answers:
Mariulka [41]3 years ago
7 0

You need to simplify both sides then isolate y by adding 4x to both side then diving both sides by 2:

2x + 5m = 2y - 4x

2x + 5m + 4x = 2y - 4x + 4x

6x + 5m = 2y

6x + 5m / 2 = 2y / 2

6x + 5m / 2 = y

So, y = 6x + 5m over 2, the second option

Hope this helps! Mark as Brainliest please! :)))

romanna [79]3 years ago
5 0

To solve 2x + 5m = 2y - 4x for y, we simply must put this equation into the y = format. To do this, we should try and isolate the variable y, as if we were solving the equation for this variable. Our first step to add 4x to both sides to get the variable term alone.

2x + 5m = 2y - 4x

2y - 4x = 2x + 5m (flip the sides of the equation)

2y = 6x + 5m

Next we must divide both sides of the equation by 2 in order to get the variable y by itself and cancel out the coefficient.

y = 6x + 5m / 2

Therefore, your answer is y = 6x + 5m / 2.

Hope this helps!

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According to a study done by Wakefield Research, the proportion of Americans who can order a meal in a foreign language is 0.47.
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Answer:

Probability that the proportion of Americans who can order a meal in a foreign language is greater than 0.5 is 0.19766.

Step-by-step explanation:

We are given that according to a study done by Wake field Research, the proportion of Americans who can order a meal in a foreign language is 0.47.

Suppose a random sample of 200 Americans is asked to disclose whether they can order a meal in a foreign language.

<em>Let </em>\hat p<em> = sample proportion of Americans who can order a meal in a foreign language</em>

The z-score probability distribution for sample proportion is given by;

          Z = \frac{ \hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion

p = population proportion of Americans who can order a meal in a foreign language = 0.47

n = sample of Americans = 200

Probability that the proportion of Americans who can order a meal in a foreign language is greater than 0.5 is given by = P( \hat p > 0.50)

  P( \hat p > 0.06) = P( \frac{ \hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } > \frac{0.5-0.47}{\sqrt{\frac{0.5(1-0.5)}{200} } } ) = P(Z > 0.85) = 1 - P(Z \leq 0.85)

                                                               = 1 - 0.80234 = <u>0.19766</u>

<em>Now, in the z table the P(Z  </em>\leq <em>x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 0.85 in the z table which has an area of 0.80234.</em>

Therefore, probability that the proportion of Americans who can order a meal in a foreign language is greater than 0.5 is 0.19766.

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