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vodomira [7]
3 years ago
15

17 of the tables at a Restaurant are full and the other 3 tables are empty. What is the ratio of the number of empty tables to t

he number of full tables?
Mathematics
1 answer:
AlladinOne [14]3 years ago
4 0

Answer:

\frac{3}{17}

Step-by-step explanation:

We have given number of full tables = 17 tables

Number of empty tables =3 tables

Total number of tables =17+3=20 tables

We have to find the ratio of empty tables to the ratio of full tables

So the ratio of empty tables to full tables =\frac{3}{17} here nominator is the number of empty tables and denominator is number of full tables  

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Answer: 300

Step-by-step explanation:

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3 years ago
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Margie threw a ball upwards while standing on a platform 65ft above the ground. The trajectory follows the​ equation:h(t)=-1.5t^
EastWind [94]

Answer:

  • 14 seconds

Step-by-step explanation:

Given equation is representing the graph of parabola which opens down and its pick is its vertex

<u>The vertex is calculated by vertex formula:</u>

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<u>In our case t is the vertex and its value is:</u>

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7 0
3 years ago
Jamie went to the his 6 friends. For each friend, he spent $4.75 for a sandwich, $1.25 for a cold beverage, and $.56 for a piece
masha68 [24]

Answer:

Jamie spent $39.36 in total.

Step-by-step explanation:

First, add the money spent for the sandwich, beverage, and fruit together.

4.75 + 1.25 + .56 = 6.56

Then, multiply the amount spent for one friend by six to find the total.

6.56 x 6 =39.36

I hope this helped you!

8 0
4 years ago
Sara bought a 25-ounce jar of strawberry jam for $4.50. What is the unit price?
fgiga [73]
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7 0
3 years ago
How would I do the steps to solve this?
allsm [11]

Answer:

The maximum revenue is 16000 dollars (at p = 40)

Step-by-step explanation:

One way to find the maximum value is derivatives. The first derivative is used to find where the slope of function will be zero.

Given function is:

R(p) = -10p^2+800p

Taking derivative wrt p

\frac{d}{dp} (R(p) = \frac{d}{dp} (-10p^2+800p)\\R'(p) = -10 \frac{d}{dp} (p^2) +800 \ frac{d}{dp}(p)\\R'(p) = -10 (2p) +800(1)\\R'(p) = -20p+800\\

Now putting R'(p) = 0

-20p+800 = 0\\-20p = -800\\\frac{-20p}{-20} = \frac{-800}{-20}\\p = 40

As p is is positive and the second derivative is -20, the function will have maximum value at p = 40

Putting p=40 in function

R(40) = -10(40)^2 +800(40)\\= -10(1600) + 32000\\=-16000+32000\\=16000

The maximum revenue is 16000 dollars (at p = 40)

3 0
3 years ago
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