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Scorpion4ik [409]
3 years ago
6

Select all the correct answers Which set of points represent one to one functions

Mathematics
1 answer:
77julia77 [94]3 years ago
6 0

Answer:

1 and 3 and 7

Step-by-step explanation:

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Please answer this and I’ll make you Brainly
murzikaleks [220]

Answer:

-4 = ?

Step-by-step explanation:

<u>Step 1:  Substitute -1 for x</u>

7x^3 + 5x^2 - 2 = ?

7(-1)^3 + 5(-1)^2 - 2 = ?

7(-1) + 5(1) - 2 = ?

-7 + 5 - 2 = ?

-4 = ?

Answer: -4 = ?

3 0
3 years ago
Pls help! will give brainlist!
sertanlavr [38]

Answer:The answer is 2 hope this helps!

Step-by-step explanation:

4 0
3 years ago
What is the distributive property of -3(8-b)
Alex787 [66]

Answer:

-24 + 3b

Step-by-step explanation:

-3 times 8 - -3 times b

-24 - -3b

and leave it alone cause its not like terms

5 0
3 years ago
In the diagram all measurements are in centimetres.
Luda [366]

Perimeter of the quadrilateral = 48 cm

Solution:

The dimensions of the quadrilateral are 2x, 2x – 1, x – 3 and 3x.

The dimensions of the triangle are x + 3, 5 and x + 3.

<em>Perimeter of the polygon = Sum of the sides of the polygon</em>

The perimeter of the quadrilateral  = 2 × Perimeter of the triangle

2x + 2x – 1 + x – 3 + 3x = 2 × (x + 3 + 5 + x + 3)

8x – 4 = 2 × (2x + 11)

8x – 4 = 4x + 22

Add 4 on both sides of the equation.

8x = 4x + 26

Subtract 4x on both sides of the equation.

4x = 26

Divide by 4 on both sides of the equation.

x = 6.5

Perimeter of the quadrilateral  = 2 × (x + 3 + 5 + x + 3)

Perimeter of the quadrilateral = 2 × (6.5 + 3 + 5 + 6.5 + 3)

                                                  = 2 × (9.5 + 5 + 9.5)

                                                  = 2 × 24

                                                  = 48

Perimeter of the quadrilateral = 48 cm

3 0
4 years ago
8. A model airplane is shot into the air. Its path is approximated by the
rjkz [21]

Here is another one of those " quadratic word problems " at hand, which is great!

By the function that is given to us ( which I believe is meant to be h(t) = - 5t^2 + 251 ) the airplane is launched at a height of 251 metres, with no velocity. Anyhow, we need to determine the duration with which the airplane will strike the ground, and to do so we can set up the following equation, - 5t^2 + 251 = 0 - solving for t, otherwise known to be the time!

See the procedure below -

-5t^2+251=0 - Subtract 251 from either side,

-5t^2=-251 - Divide either side by - 5,

t^2=\frac{251}{5} - And, now isolate t, receiving two solutions,

t=\sqrt{\frac{251}{5}},\:t=-\sqrt{\frac{251}{5}}

However, time can't be a negative value. Thus our solution is \sqrt{251 / 5}, which is ( about ) 7.085 seconds!

3 0
3 years ago
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