Answer:
is the closest to 8
Step-by-step explanation:

Y = e^tanx - 2
To find at which point it crosses x axis we state that y= 0
e^tanx - 2 = 0
e^tanx = 2
tanx = ln 2
tanx = 0.69314
x = 0.6061
to find slope at that point first we need to find first derivative of funtion y.
y' = (e^tanx)*1/cos^2(x)
now we express x = 0.6061 in y' and we get:
y' = k = 2,9599
Answer:
48.8 lbs
Step-by-step explanation:
The forces can be modeled by a triangle with acute angles 20° and 26°, and obtuse angle 134° opposite a side of length 80. The larger component force will be opposite the angle 26°, and can be found using the Law of Sines:
a/sin(A) = c/sin(C)
x/sin(26°) = 80/sin(134°)
x = 80sin(26°)/sin(134°) ≈ 48.753 . . . . pounds
The larger component force is about 48.8 pounds.
Answer:The function is nonlinear
Step-by-step explanation:
Took the test made a 100