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3 years ago

Can 31/50 be simplified

2 answers:

7 0

No because when one number is odd and the other one is even it can't be simplified (unless they are multiples/factors of each other) ex: 7/14

user100 [1]3 years ago

3 0

No, 31, a prime number, can not be divided any more to become another numerator, not to mention having to correspond with 50 as well.

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A tree that is 100 feet tall casts a shadow that is 150 feet long. Determine the angle at which the rays of the sun hit the grou

Dvinal [7]

Answer:

Step-by-step explanation:

A tree that is 100 feet tall casts a shadow that is 150 feet long ...

The angle at which the ray of the sun hit the ground is that which has a tangent equal to 100 / 150 or 2/3. This angle is equal to 33.69. Thus, the answer is letter B. 34°

5 0

3 years ago

Read 2 more answers

Divide 110 g of salt in ratio 5 : 8 : 9; what is the result ?

vekshin1

110grams÷22 =5

5+8+ 9 =22

5 x5=25

5x8=40

5x9=45

The ratio is 25:40:45

5 0

3 years ago

Solve for x.<br><br> x+23=−22<br><br> someone help

BaLLatris [955]

Answer:

x = - 45

Step-by-step explanation:

x+23(-23)=−22 (-23)First subtract 23 from both sides

x = - 45

7 0

3 years ago

Y is directly proportional to x.

djyliett [7]

Answer:

Step-by-step explanation:

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3 0

3 years ago

given the recursive formula for a geometric sequence find the common ratio the 8th term and the explicit formula.did I set these

lesya [120]

Answer:

Step-by-step explanation:

1)Since we know that recursive formula of the geometric sequence is

$a_{n}=a_{n-1}*r$

so comparing it with the given recursive formula $a_{n}=a_{n-1}*-4$

we get common ratio =-4

8th term= $a_{1}*(r)^{n-1}=-2*(-4)^{7} =32768.$

Explicit Formula = $-2*(-4)^{n-1}$

2) Comparing the given recursive formula $a_{n}=a_{n-1}*-2$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-2

8th term= $a_{1}*(r)^{n-1}=-4*(-2)^{7} =512.$

Explicit Formula = $-4*(-2)^{n-1}$

3)Comparing the given recursive formula $a_{n}=a_{n-1}*3$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =3

8th term= $a_{1}*(r)^{n-1}=-1*(3)^{7} =-2187.$

Explicit Formula = $-1*(3)^{n-1}$

4)Comparing the given recursive formula $a_{n}=a_{n-1}*-4$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-4

8th term= $a_{1}*(r)^{n-1}=3*(-4)^{7} =-49152.$

Explicit Formula = $3*(-4)^{n-1}$

5)Comparing the given recursive formula $a_{n}=a_{n-1}*-4$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-4

8th term= $a_{1}*(r)^{n-1}=-4*(-4)^{7} =65536.$

Explicit Formula = $-4*(-4)^{n-1}$

6)Comparing the given recursive formula $a_{n}=a_{n-1}*-2$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-2

8th term= $a_{1}*(r)^{n-1}=3*(-2)^{7} =-384.$

Explicit Formula = $3*(-2)^{n-1}$

7)Comparing the given recursive formula $a_{n}=a_{n-1}*-5$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-5

8th term= $a_{1}*(r)^{n-1}=4*(-5)^{7} =-312500.$

Explicit Formula = $4*(-5)^{n-1}$

8)Comparing the given recursive formula $a_{n}=a_{n-1}*-5$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-5

8th term= $a_{1}*(r)^{n-1}=2*(-5)^{7} =-156250.$

Explicit Formula = $2*(-5)^{n-1}$

6 0

3 years ago