Given:
The power generated by an electrical circuit (in watts) as function of its current x (in amperes) is modeled by:
To find:
The current that will produce the maximum power.
Solution:
We have,
Here, leading coefficient is negative. So, it is a downward parabola.
Vertex of a downward parabola is the point of maxima.
If a parabola is , then
In the given function, a=-12 and b=120. So,
Putting x=5 in the given function, we get
Therefore, 5 watt current will produce the maximum power of 300 amperes.
Answer:
x = -33
Step-by-step explanation:
2/3(x+6) = -18
multiply (x+6) by 2/3
2/3x + 4 = -18
subtract 4 from both sides
2/3x + 4 - 4 = -18 - 4
2/3x = -22
multiply by 3/2
2/3 x 3/2 x = -22 x 3/2
x = -33
The Answer is C) 6 I believe
Photomath is useful for these kinds of problems