Answer:
116
Step-by-step explanation:
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The variables in these questions are
1. m
2. v
3. y
4. p
5. k
Add 3 to both sides so that the equation becomes 2x^2 + 7x - 6 = 0.
To find the solutions to this equation, we can apply the quadratic formula. This quadratic formula solves equations of the form ax^2 + bx + c = 0
x = [ -b ± √(b^2 - 4ac) ] / (2a)
x = [ -7 ± √(7^2 - 4(2)(-6)) ] / ( 2(2) )
x = [ -7 ± √(49 - (-48) ) ] / ( 4 )
x = [ -7 ± √(97) ] / ( 4)
x = [ -7 ± sqrt(97) ] / ( 4 )
x = -7/4 ± sqrt(97)/4
The answers are -7/4 + sqrt(97)/4 and -7/4 - sqrt(97)/4.
A <span>counterclockwise rotation of 270º about the origin is equivalent to a </span><span>clockwise rotation of 90º about the origin.
Given a point (4, 5), the x-value, i.e. 4 and the y-value, i.e. 5 are positive, hence the point is in the 1st quadrant of the xy-plane.
A clockwise rotation of </span><span>90º about the origin of a point in the first quadrant of the xy-plane will have its image in the fourth quadrant of the xy-plane. Thus the x-value of the image remains positive but the y-value of the image changes to negative.
Also the x-value and the y-value of the original figure is interchanged.
For example, given a point (a, b) in the first quadrant of the xy-plane, </span><span>a counterclockwise rotation of 270º about the origin which is equivalent to a <span>clockwise rotation of 90º about the origin will result in an image with the coordinate of (b, -a)</span>
Therefore, a </span><span>counterclockwise rotation of 270º about the origin </span><span>of the point (4, 5) will result in an image with the coordinate of (5, -4)</span> (option C)
