X cube+6x-16=0
2 answers:
Answer:
(b) {-8, 2}
Step-by-step explanation:
The given equation
x³ +6x -16 = 0
cannot be factored in integers. It has one irrational real root near x=1.759, and two complex roots.
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Perhaps you want to factor ...
x² +6x -16 = 0
(x +8)(x -2) = 0
This has solutions x = -8 and x = 2 that make the factors be zero.
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<em>Additional comment</em>
"Cubed" refers to an exponent of 3.
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Answer:
A. Discriminant = 116
B. Number of solutions for the quadratic equation = 2
C. Type of solutions (circle one):Imaginary
D. Type of solutions (circle one):irrational
Step-by-step explanation:
The given quadratic equation is
We rewrite in standard form to get;
The discriminant is
where a=1, b=8, c=-13
We substitute to get:
Since the discriminant is great than zero, we have two distinct real roots