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2 years ago

12

X cube+6x-16=0

2 answers:

Aleksandr-060686 [28]2 years ago

4 0

Answer:

(b) {-8, 2}

Step-by-step explanation:

The given equation

x³ +6x -16 = 0

cannot be factored in integers. It has one irrational real root near x=1.759, and two complex roots.

__

Perhaps you want to factor ...

x² +6x -16 = 0

(x +8)(x -2) = 0

This has solutions x = -8 and x = 2 that make the factors be zero.

_____

<em>Additional comment</em>

"Cubed" refers to an exponent of 3.

Reil [10]2 years ago

4 0

Answer:

Option b] (2,-8)

Step-by-step explanation:

⇒ x³ + 6x - 16 = 0

♦ the value of one root is irrational and other two are complex roots.

⇒ x² + 6x - 16 = 0

⇒ (x + 8)(x - 2) = 0

⇒ x = 2 , -8

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2 years ago

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-BARSIC- [3]

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3 years ago

-22 + (-16)<br> Hhhhhhhhhhhhhhhhhhhhhh

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2 years ago

Read 2 more answers

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I realize I'm a year late, but the math of the previous answer was so terrible I'm honestly too horrified to let this be.

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n= term you want

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