X cube+6x-16=0
2 answers:
Answer:
(b) {-8, 2}
Step-by-step explanation:
The given equation
x³ +6x -16 = 0
cannot be factored in integers. It has one irrational real root near x=1.759, and two complex roots.
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Perhaps you want to factor ...
x² +6x -16 = 0
(x +8)(x -2) = 0
This has solutions x = -8 and x = 2 that make the factors be zero.
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<em>Additional comment</em>
"Cubed" refers to an exponent of 3.
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Write an equation for the line that passes through (0, 1) and has a slope of 2 (in point-slope form).
<u>Point-slope form</u>:-
Substitute 1 for y₁, 2 for m, and 0 for x₁:-
So we conclude that Option B is correct.
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