Answer:
- complement: 32.8°
- supplement: 122.8°
Step-by-step explanation:
The sum of an angle A and its complement C is 90°:
A + C = 90°
C = 90° -A . . . . . subtract A from both sides.
That is, the complement of an angle is found by subtracting the angle from 90°.
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The sum of an angle and its supplement is 180°. This means the supplement of an angle is found by subtracting the angle from 180°. You may notice the supplement is 90° more than the complement.
A + S = 180°
S = 180° -A = 90° +(90° -A)
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For the given angle, the complement is ...
C = 90° -57.2° = 32.8°
And the supplement is ...
S = 180° -57.2° = 122.8°
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<em>Additional comment</em>
We generally like angle measures to be positive (as with all measures in geometry). Hence, we might say that the complement of an angle greater than 90° does not exist. YMMV
1 - (1/4 + 2*1/4)
1 - 3/4
1/4 of the living room still remains unpainted.
Since every side of a square is the same length, and the formula to find the area is bh you would just do 2.75²
2.75×2.75=7.5625≈7.56
the answer is the area of the square is approximately 7.56u²
Answer:
1.8
Step-by-step explanation:
slope formula: (y2-y1)/(x2-x1)
(86-32)/(30-0)
54/30
1.8
Answer:
This problem is incomplete, we do not know the fraction of the students that have a dog and also have a cat. Suppose we write the problem as:
"In Mrs.Hu's classroom, 4/5 of the students have a dog as a pet. X of the students who have a dog as a pet also have cat as a pet. If there are 45 students in her class, how many have both a dog and a cat as pets?"
Where X must be a positive number smaller than one, now we can solve it:
we know that in the class we have 45 students, and 4/5 of those students have dogs, so the number of students that have a dog as a pet is:
N = 45*(4/5) = 36
And we know that X of those 36 students also have a cat, so the number of students that have a dog and a cat is:
M = 36*X
now, we do not have, suppose that the value of X is 1/2 ("1/2 of the students who have a dog also have a cat")
M = 36*(1/2) = 18
So you can replace the value of X in the equation and find the number of students that have a dog and a cat as pets.
