We could find the slope with this formula
m = (y₂ - y₁)/(x₂ - x₁)
with (x₁,y₁) and (x₂,y₂) are the points that is located on the line.
NUMBER 20
Given:
(x₁,y₁) = (-2,3)
(x₂,y₂) = (7,-4)
Solution:
Input the points to the formula
m = (y₂ - y₁) / (x₂ - x₁)
m = (-4 - 3) / (7 - (-2))
m = -7 / (7+2)
m = -7/9
The slope of the line is -7/9
NUMBER 21
Given:
(x₁,y₁) = (-6,-1)
(x₂,y₂) = (4,1)
Solution:
Input the points to the formula
m = (y₂ - y₁) / (x₂ - x₁)
m = (1-(-1)) / (4 -(-6))
m = (1+1) / (4+6)
m = 2/10
m = 1/5
The slope of the line is 1/5
NUMBER 22
Given:
(x₁,y₁) = (-9,3)
(x₂,y₂) = (2,1)
Solution:
Input the points to the formula
m = (y₂ - y₁) / (x₂ - x₁)
m = (1 - 3) / (2 - (-9))
m = -2 / (2 + 9)
m = -2/11
The slope of the line is -2/11
In this case, h(x) = sqrt(x) + 3
A. f(x)=x+3; g(x)=√x
B. f(x)=x; g(x)=x+3
C. f(x)=√x; g(x)=x+3
D. f(x)=3x; g(x)=√x
Again, you need to find a function f(x) that once evaluated in g(x) gives us h(x)
h(x) = g(f(x))
Looking at the options, the answer is C.
g(f(x)) = f(x) + 3 = sqrt (x) + 3 = h(x)
30.56 hope i helped my gurl
The horizontal asymptote is y=-2
