Question:
Morgan is playing a board game that requires three standard dice to be thrown at one time. Each die has six sides, with one of the numbers 1 through 6 on each side. She has one throw of the dice left, and she needs a 17 to win the game. What is the probability that Morgan wins the game (order matters)?
Answer:
1/72
Step-by-step explanation:
<em>Morgan can roll a 17 in 3 different ways. The first way is if the first die comes up 5, the second die comes up 6, and the third die comes up 6. The second way is if the first die comes up 6, the second die comes up 5, and the third die comes up 6. The third way is if the first die comes up 6, the second die comes up 6, and the third die comes up 5. For each way, the probability of it occurring is 1/6 x 1/6 x 1/6 = 1/216. Therefore, since there are 3 different ways to roll a 17, the probability that Morgan rolls a 17 and wins the game is 1/216 + 1/216 + 1/216 = 3/216 = 1/72</em>
<em>I had this same question on my test!</em>
<em>Hope this helped! Good Luck! ~LILZ</em>
Answer: -5 - (-10 )= 5
Step-by-step explanation:
The arrows on the number line stops at -5 and -10 so you subtract -5 minus -10 and get your anwser 5
23/6 as a mixed number equals 3 5/6
24/4 → 4 goes into 24 6 times so the answer is 6
Based on the central angle theorem, the measure of angle AEB is: 140°.
<h3>What is the Central Angle Theorem?</h3>
According to the central angle theorem, the measure of an intercepted arc = measure of the central angle.
Arc AB = 140° [intercepted arc]
Angle AEB is the central angle.
Thus, based on the central angle theorem, the measure of angle AEB is: 140°.
Learn more about the central angle theorem on:
brainly.com/question/5436956
#SPJ1
-sinx + C
hope this helps!
