Answer:
At the 3rd day 160 students caught flu.
Step-by-step explanation:
Consider the provided model P = − t ² + 13t + 130 where 1 ≤ t ≤ 6
The total number of students is represents by P.
We need to find the day that 160 students had the flu.
Substitute the value of P=160 in above formula.






Hence the value of t=10 or t=3
But it is given that 1 ≤ t ≤ 6, Therefore select t=3
Hence, at the 3rd day 160 students caught flu.
Answer:
14 years
Step-by-step explanation:
If the value of the car is $28,000 and each year the value goes down by $2,000 it will be $0 in 14 years. 28/2=14
Good Question!
So since we know that a square is exactly the same all the way around we can assume that both diagonals in the square are the same. This means that they form a right triangle in the middle with two legs of 3.75!
So to find the side of the triangle we use a^2 + b^2 = c^2
3.75^2 + 3.75^2 = c^2
28.125 = c^2
<span>√(28.125) = c
</span>c = 5.3
Now finally we just square 5.3 again to find the area of the square and it's 28.1mm^2!
So the answer is the third one! hope this helps!
Answer:
y=3
Step-by-step explanation:
it says that y is the inverse of x so if x=3 and y=8, so if x=8 than y must equal 3
9514 1404 393
Answer:
- f(0) ≈ 22
- f(1) = 10
- f(b) ≈ -8
- f(c) = 0
- f(d) 24
Step-by-step explanation:
This takes graph-reading one step further. You get to estimate the y-value without benefit of minor grid lines. You must mentally divide the 10-unit distance between grid lines into equal spaces. Then estimate how many of those spaces lie between the point and the nearest grid line.
You can do this more precisely by drawing a diagonal line across the grid from one major grid intersection to one that is (5, 1) or (5, -1) major grid points away. Where that line crosses the intermediate grid lines, the vertical measure will be some multiple of 1/5 of the vertical difference between grid points. For example, a line from (0,20) to (5,30) will cross at (1,22), (2,24), (3,26), and (4,28). You can use these reference points to identify the y-values at f(0) and f(d).
Here's our eyeball estimate:
- f(0) ≈ 22
- f(1) = 10
- f(b) ≈ -8
- f(c) = 0
- f(d) 24